I saw on your other question that you mention <em>y</em> (0) = 0. Let
<em>f(x</em>, <em>y)</em> = <em>x</em> + <em>y</em> ²
Now consider the recurrences in Euler's method,
where <em>h</em> is the step size.
We then approximate <em>y</em> (0.2) in ...
• ... 2 steps for <em>h</em> = 0.1 :
so that <em>y</em> (0.2) ≈ 0.01;
• ... 4 steps for <em>h</em> = 0.05 :
so <em>y</em> (0.2) ≈ 0.015.
Answer:
10.1
<em>hope this helps!</em>
Because you're multiplying
by
.
is
,
is
is
. Since you're multiplying them all together, it doesn't matter what order you multiply them in. For example,
,
, and [2x*4x=8x^2[/tex] (but that's just the same.)
<em>
</em><em>Hope that helps! :)</em>
Answer:
185
Step-by-step explanation:
firstly you calculate all in brackets
(280+20)÷3
300÷3
100-15
85
now you calculate 10×5=50
2×50=100
85+100=185
so firstly deal with problem inside the brackets, then you got multiplication and division outside their brackets and finally get 85 +100 =185
Answer:
C. x²+3x-28
Step-by-step explanation:
f(x) = x +7
g(x) = x -4
f(x) · g(x) = (x-4)(x+7)
= x²+7x-4x-28
= x²+3x-28