Answer:
Vertex (-2.5,-300)
Step-by-step explanation:
We are given with h(t)=-16 t^2 +80 t. We are asked to find the vertex.
X-coordinate of vertex =
Where 'a' is coefficient of 
term
'b' is coefficient of 't' term.
From given function, a= -16
b=80
So,
x-coordinate of vertex =
=-2.5
y-coordinate of vertex =
Simplify it,
=-100 -200
= -300
So, vertex is at (-2.5, -300).
hi,
Express the ratios in fractional form, that is
= ( cross- multiply )
y + 3 = k(y + 5) ← distribute
y + 3 = ky + 5k ( subtract ky from both sides )
y - ky + 3 = 5k ( subtract 3 from both sides )
y - ky = 5k - 3 ← factor out y from each term on the left side
y(1 - k) = 5k - 3 ← divide both sides by (1 - k)
y = 5k- 3
____
1 - k
Answer:
<em>*****Slope: M = -3*****</em>
Answer:
the answer is D 1/27
Step-by-step explanation:
