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2 years ago

Can someone plz help in part a b c thank u somuvhhhhh

Mathematics

2 answers:

docker41 [41]2 years ago

5 0

Part a= the inequality would be 42=2x-10
part b= 42=2x-10
-10 -10
(32=2x) 2
16

MrMuchimi2 years ago

5 0

Who Cox!,! the way I will have been sent via a new one day of your browser such an account registration number and then you have

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PLEASE CHECK AND SEE IF I'M CORRECT!!! <br> CORRECT ANSWERS ONLY PLEASE!!!

jeka57 [31]

BD is right but PA is wrong, would be BD and MK.

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2 years ago

Help me with this please !!

avanturin [10]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the line y = - x

a point (x, y ) → (- y, - x ), thus

T(- 1, 3 ) → T'(- 3, 1 )

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3 years ago

A diver is 5 feet above the surface of a pool. If his position can be recorded as 5 feet, what would the position of 0 represent

WARRIOR [948]

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3 years ago

Read 2 more answers

Which expression is equivalent to (81x4y16)12 for all positive values of x and y?<br> 40.5x4y16

IrinaVladis [17]

Answer:

$(81x^4y^{16})^{\frac{1}{2}} = 9 x^2 y^8$

Step-by-step explanation:

Given

$(81x^4y^{16})^{\frac{1}{2}}$

Required

Determine an equivalent expression

Express 81 as $9^2$

$(9^2x^4y^{16})^{\frac{1}{2}}$

Apply law of indices

$9^2^{\frac{1}{2}} * x^4^{\frac{1}{2}} * y^{16}^{\frac{1}{2}}$

$9^{\frac{2*1}{2}} * x^{\frac{4*1}{2}} * y^{\frac{16*1}{2}}$

$9^{\frac{2}{2}} * x^{\frac{4}{2}} * y^{\frac{16}{2}}$

$9^1 * x^2 * y^8$

$9 * x^2 * y^8$

$9 x^2 y^8$

Hence:

$(81x^4y^{16})^{\frac{1}{2}} = 9 x^2 y^8$

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2 years ago

Plz help w this math problem

Svetllana [295]

Answer:

• for x = 2a√t, make t the subject:

${ \tt{x = 2a \sqrt{t} }} \\ \\ { \tt{ \sqrt{t} = \frac{x}{2a} }} \\ \\ { \boxed{ \tt{t = \frac{ {x}^{2} }{4 {a}^{2} } }}}$

• then find y:

${ \tt{y = {ar}^{2} - 2at}} \\ \\ { \tt{y = {ar}^{2} - 2a( \frac{ {x}^{2} }{4 {a}^{2} } ) }} \\ \\ { \boxed{ \tt{y = {ar}^{2} - \frac{ {x}^{2} }{2a} }}}$

6 0

2 years ago