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Arisa [49]
3 years ago
14

Which new angle is created by extending one side of a triangle

Mathematics
2 answers:
zhuklara [117]3 years ago
6 0
An exterior angle. 87% Sure.
Phoenix [80]3 years ago
4 0
An<u> exterior angle </u>would be created. The two remote interior angles(not the one touching/adjacent) add up to the degree measure of the exterior angle. Complimentary angles sum add to 90 degrees
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Select the two statements that are true about the equation −10=60(−40)
Aleksandr-060686 [28]

Answer:

The slope of the line is 60  

One point on the line is (40, 10)  

Step-by-step explanation:

The missing choices are :

1) The slope of the line is 10  

2)One point on the line is (40, 10)  

3)The slope of the line is 60  

4)One point on the line is (10, 60)

Given the equation y−10=60(x−40),  applying distributive property we get:

y−10=60x - 60*40

t = 60x - 2400 + 10

t = 60x - 2390

The slope is the number that multiplies x, that is, 60.

To check if the point (40, 10) belongs to the equation, replace the values x = 40 and y = 10 in the equation, as follows:

(10)−10=60((40)−40)

0 = 0

The same number appear at both sides of the equal sign,  then the point (40, 10) is on the line. Analogously, for point (10, 60):

(60)−10=60((10)−40)

50 = 60*(-30)

50 = -1800

The two numbers are different, then, the point (10, 60) is not on the line.

4 0
3 years ago
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Out of a group of 30 volunteers, 17 people are chosen to participate in a survey about the number of phone calls they make each
mel-nik [20]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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Which statements are true about the interquartile range? Select all that apply.​
kap26 [50]
Is there a picture? there's not enough info
4 0
3 years ago
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A) y=5x+5<br> B)y=x+5<br> C)y=5x+25<br> D)y=x+125
kirill115 [55]
The answer of the question is C
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The endpoints of a regular pentagon are (-1,4) and (2,3). What is the perimeter of the Pentagon?
ryzh [129]

the assumption being that the endpoints are two continuous points in the pentagon, Check picture below.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[2-(-1)]^2+[3-4]^2}\implies d=\sqrt{(2+1)^2+(3-4)^2} \\\\\\ d=\sqrt{9+1}\implies d=\sqrt{10}~\hfill \stackrel{\stackrel{~\hfill \stackrel{\textit{5 sides}}{}}{\textit{perimeter of the pentagon}}}{5\sqrt{10}}

4 0
3 years ago
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