Collin wants to solve this system of equations. Which number can he multiply the first equation by so that when the two equation
s are added together, the x term is eliminated? One-half x + one-fourth y = 5 2 x + three-eighths y = 5 –4 –2 2
2 answers:
Answer:
-9
Step-by-step explanation:
Answer:
-4
Step-by-step explanation:
The given equations are as follows:
![\[\frac{1}{2}x+\frac{1}{4}y=5\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B1%7D%7B2%7Dx%2B%5Cfrac%7B1%7D%7B4%7Dy%3D5%5C%5D)
![\[2x +\frac{3}{8}y=5\]](https://tex.z-dn.net/?f=%5C%5B2x%20%2B%5Cfrac%7B3%7D%7B8%7Dy%3D5%5C%5D)
The coefficient of x in the second equation is 2.
So in order to eliminate x we need to multiply the first equation by a value so that the coefficient of x becomes -2.
Since the coefficient of x in the first equation is \[\frac{3}{8}\], it needs to be multiplied by -4.
So the required multiplier for the first equation is -4
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To regroup is to use place value to exchange equal amount when renaming a number.
Answer: 24y - 8w + 16
Step-by-step explanation:
Basically to remove the parenthesis you just distribute the -4 outside of the parenthesi and you get 24y - 8w + 16.
Answer:
75
Step-by-step explanation:
Answer:
16m
Step-by-step explanation:
4 x 2 = 8
8 x 2 = 16
Sub (x+1) for x
f(x+1)=2(x+1)^2+3
f(x+1)=2(x^2+2x+1)+3
f(x+1)=2x^2+4x+2+3
f(x+1)=2x^2+4x+5
D is answer
