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kirza4 [7]
3 years ago
11

Patty bought a "P" poster to put on her wall, as shown below.

Mathematics
1 answer:
kolezko [41]3 years ago
7 0

The area of the poster is B. 535.5 in².

Step-by-step explanation:

Step 1:

The poster consists of a rectangle and three-quarters of a circle.

The rectangle has a length of a and width of 3a. The circle has a radius of a.

We calculate the areas of the individual shapes and sum them up to calculate the entire area of the poster.

Step 2:

The area of a rectangle is the product of its length and its width.

If a = 10 inches, the length is 10 inches and the width is 30 inches.

The area of the rectangle = (l)(w) = (10)(30)= 300.

The area of the rectangle is 300 in².

Step 3:

The area of a circle = \pi r^{2} . Here we only have three-quarters of a circle, so

The area of the given circle =\frac{3}{4} ( \pi r^{2} ).

Here r = a = 10 inches.

So the area of the circle =\frac{3}{4} ((3.1415) (10^{2}) ) = 235.6125.

The area of the circle is 235.6125 in².

Step 4:

The total area of the shape = The area of the rectangle + The area of the circle.

The total area of the shape = 300 + 235.6125 = 535.6125.

So the area of the poster is B. 535.5 in².

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Who packed all the pies? Kane’s bakery makes four flavour pies. The weight of each flavour pie is follows:
svet-max [94.6K]
This is an identical problem answered by myself a few days ago.  The answer is reproduced below for your convenience.

It is a very difficult problem if the box sizes are smaller or if there are more pies to pack.
For this particular problem, we first calculate the total weight of pies:
4 apple pies at 700 g = 2800 g
8 banoffee pies at 725 g =5800 g
3 custaard pies at 600 g = 1800 g
5 rhubarb pies at 675 g = 3375 g
for a total of 13775 g

The minimum number of boxes needed will be 13775/4000=3.44, or at least 4 boxes will be required.

We also note that 4 boxes will hold 16000 g, and we only need to pack 13775g, so there is a lot of margin.

We can proceed to do the mechanical way, fill in order of apple, banoffee, custard, and finally rhubarb pies.Following table shows how we fill, naively:      box content               Remaining to pack
Box A B C R     Weight    A B C R   
0                                      4  8  3 5     (original order)
1     4  1  0 0     3525       0  7  3 5
2     0  5  0 0     3625       0  2  3 5
3     0  2  3 0     3250       0  0  0 5
4     0  0  0 5     3375       0  0  0 0
Total weight     13775 g

So that does the job, 4 boxes (minimum) with none exceeding 4000 g to pack a total of 13775 g of pies.
 
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