Plz, help! I don't know this ! will give brainlest!

In the 2017 fiscal year, the state of Alaska received $8.2 billion In revenues and had $7.2 billion in expenditures. What percen

konstantin123 [22]

To figure this out you can do 7.2/8.2, because you are trying to figure out how much of the total was used, and percentages would not be more than 100%. Doing this you would get ~.878. To convert this to a percent, you would just multiply it by 100, which would give you 87.8%. The question states to round to the nearest whole percent, leaving you with 88%. This means that 88% of the revenue was spent.

Hope that helped, don't be shy to comment on this if you have any questions about my explanation :)

8 0

3 years ago

I need to find what is equal to m

USPshnik [31]

Answer: 0

Step-by-step explanation:

Point A = (3 , 4)

Point B = (7 , 4)

$\frac{yB - yA}{xB - xA}$ = $\frac{0}{5}$

5 0

3 years ago

Find area of triangle

ivanzaharov [21]

Answer:

49.1 cm² (round to nearest 10)

Step-by-step explanation:

- use trigonometry to find the height(h) of the triangle

- substitute height and base(b) 12cm into the formula

A = ½ × b × h .

7 0

3 years ago

Jamarius just filled up his SUV for $58.56. If he put 24 gallons of gas in the tank, what was the cost per gallon?

Kazeer [188]

Answer:

$2.44/gal

Explanation:

$58.56/24gallon/

6 0

2 years ago

A random sample of 25 ACME employees showed the average number of vacation days taken during the year is 18.3 days with a standa

Norma-Jean [14]

Answer:

a) Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

b) $df=n-1=25-1=24$

For this case the p value is given $p_v = 0.0392$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.

c) Type I error, also known as a “false positive” is the error of rejecting a null hypothesis when it is actually true. Can be interpreted as the error of no reject an alternative hypothesis when the results can be attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

Step-by-step explanation:

Data given and notation

$\bar X=18.3$ represent the sample mean

$s=3.72$ represent the sample standard deviation

$n=25$ sample size

$\mu_o =15$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a: State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean for vacation days is higher than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Part b: P-value and conclusion

The first step is calculate the degrees of freedom, on this case:

$df=n-1=25-1=24$

For this case the p value is given $p_v = 0.0392$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.

Part c

Type I error, also known as a “false positive” is the error of rejecting a null hypothesis when it is actually true. Can be interpreted as the error of no reject an alternative hypothesis when the results can be attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

3 0

3 years ago