Answer:
The genotype of both parents is RrYy.
The possible types of gametes would be RY, Ry, rY, and ry.
The cross would produce offspring that can have one out of four types of phenotypes:
- Round and yellow seeds (1 RRYY+ 2 RrYY +2 RRYy + 4 RrYy) = 9/16
- Wrinkled and yellow seeds (3 rrYy) = 3/16
- Round and green seeds (1 RRyy + 2 Rryy) = 3/16
- Wrinkled and green seeds (rryy) = 1/16
Thus, one out of 16 offspring would have wrinkled and green seeds.
Answer:
B. Putting the bacterium through a mass spectrometer.
Explanation:
FOR OBSERVATION AND TO CHECK THE RECOMBINANT DNA PROCESS WE HAVE TO THE OBSERVE THE REPLICATION PROCESS OF BACTERIA.
Is that they all have the same routine
Answer:
they eat meat, they are living oranisims, they need food to survive, they have similar teeth,
Explanation:
B) The positive charge of the protons in the nucleus equals the negative charge in the electron cloud.
(I just took the test and it was right). :)
