No there just has to be one or two on the line
Answer:
See explanation.
Step-by-step explanation:
We are looking at a geometric distribution.
The probability of selecting a brown peanut is .12 = p
The probability of not selecting a brown peanut is .88 = q
The probability mass function is p(y) = (.88)^(y-1) * (.12)
a) p(7) = (.88)^6 * .12 = .0557
b) p(7 <= y <= 8) = p(7) + p(8)
= .0557 + (.88)^7 * .12 = .1048
c) p(y <= 7) = p(0) + p(1) + ... + p(7)
= .12 + (.88)^1 * .12 + (.88)^2 * .12 + ... + (.88)^6 * .12 = .4713
d) The expect value is 1/p. So, 1/(.12) = 8.33 M&M's
Answer:
you can split the garden in: 1/2 circles x 4 (because you have 4 half-circles) + a square.
the square's area is 4 x 4 = 16; the circles is pi x R x R (pi = aprox 3.14, R of the cirlce is 4m / 2 = 2m, because the square's side is 4m and is the same size with circle diagonale: Diag of circle = 2 X Radius => Radius = Diag / 2)
than answer will be: 16 + 3.14 x 2 x 2 x 2 (the last 2 is, because you have 4 halves of circles, than you will have 2 full circles) = 45.12, than answer is H, because 41 is the nearest number to 45.12
Answer:
Plot the given point.
Use the slope formula to identify the rise and the run.
Starting at the given point, count out the rise and run to mark the second point.
Connect the points with a line.
Step-by-step explanation:
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