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3 years ago

12

if a seed is planted it has a 75% chance of growing into a healthy plant. If 7 seeds are planted what is the probability that ex

actly 4 don't grow

1 answer:

Colt1911 [192]3 years ago

5 0

NCr*P^r*q^(n-r)
7C4*. 75^4*. 25^(7-4)
35*. 75⁴*. 25³
35*. 316*. 016
11.06*. 016
. 1769
=. 177

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4⁄8 + ¼ = ? What would the answer be?

Lorico [155]

3/4. 4/8= 2/4. so 1/4+2/4=3/4

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3 years ago

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paul , Nadia and Jim have some stickers. Nadia has 3 times as many stickers as jim. Paul has 25 stickers more that Nadia. Paul a

alexandr402 [8]

Nadia = 3x than Jim
Paul = 25+ than Nadia
Jim = ?
Nadia and Paul = 85

85-25 = 60
(Subtract Nadia's and Paul's stickers all together with the stickers that Paul have more so both of the stickers are balance)

Nadia = 60/2 =30
Paul = 30+25 =55

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#Jim have 10 stickers

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3 years ago

The vertices of the triangle are given. determine whether the triangle is an acute traignel, obtuse triangle

Brrunno [24]

What are the angles?

if all of them are below 90 degrees, it is acute.

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if one angle is more than 90 degrees, it is obtuse

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3 years ago

Let R be the event that a randomly chosen person lives in the city of Raleigh. Let O be the event that a randomly chosen person

Anit [1.1K]

Answer:

P(O|R)

Step-by-step explanation:

The conditional probability notation of two events A and B can be written as either P(A|B) or P(B|A).

The '|' sign is read as 'given'. So, P(A|B) is read as the probability of event A given event B which implies that it is the probability that event A will occur given that event B has already occurred.

In the question,

Event R = Person lives in the city of Raleigh

Event O = Person is over 50 years old

The statement says, 'given that the person lives in Raleigh' which means that event R has already occurred and we need to find the probability of event O (the randomly chosen person is over 50 years old).

Hence, this statement can be given in conditional probability notation as

P(O|R)

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2 years ago

State whether the triangles could be proven congruent, if possible, by SSS or SAS.

Helen [10]

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW Given

Side FP ≅ Side CM Given

Side YP ≅ Side MW Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT Given

Side SV ≅ Side SV by reflexive property

Side VT ≅ Side VU Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP Given

Side MQ ≅ Side NP Given

Side NQ ≅ Side NQ by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL Given

Side GJ ≅ Side HK Given

∠JLG ≅ ∠HLK vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ by reflexive property

Side ZW ≅ Side ZY Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

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2 years ago