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3 years ago

Find the remainder of (x4 – 2) ÷ (x + 1).

1 answer:

5 0

Please write (x4 – 2) ÷ (x + 1) as <span>(x^4 – 2) ÷ (x + 1).

We can find the remainder using synth. div. as follows:

_________________
-1 / 1 0 0 0 -2
-1 1 -1 1
------------------------------
1 -1 1 -1 -1

The remainder is -1.</span>

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Points A and B are graphed points on the coordinate plane below. Which ordered pair is the coordinate location which is halfway

Setler [38]

Answer:

I cant see the image it doesnt seem to be loading but here is how to do the problem-->.

Add both the x coordinates and divide by 2 (this is the new x coordinate for the midpt)

Add both y coordinates and divide by 2(this is the new y coordinate for the midpt)

Step-by-step explanation:

5 0

3 years ago

SOVA2 [1]

Answer:

The shortest whole number height that will hold the fishing pole is 5 feet.

Step-by-step explanation:

Please see the attached files for details

4 0

3 years ago

What is 2 thirds plus 3 fourths

Zina [86]

In order to find this you need to find a common denominator. 2/3 and 3/4 common denominator would be 12 and so what you do to the bottom you must do to the top. 2x4 is 8 and 3x3 is 9. that would make 8/12 and 9/12. 8 plus nine is 17 and 12 stays there so the answer is 17/12 which equals 1 and 5/10.

8 0

3 years ago

Read 2 more answers

Please solve this<br> (Rational numbers 8th grade)

pochemuha

Question # 1

Answer:

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}$

Step-by-step explanation:

Given the expression

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$

$=-\frac{2}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$ ∵ $\frac{-2}{3}\times \frac{3}{5}=-\frac{2}{5}$

$=-\frac{2}{5}+\frac{1}{4}$ ∵ $\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=\frac{1}{4}$

$\mathrm{Least\:Common\:Multiplier\:of\:}5,\:4:\quad 20$

$=-\frac{8}{20}+\frac{5}{20}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-8+5}{20}$

$\mathrm{Add/Subtract\:the\:numbers:}\:-8+5=-3$

$=\frac{-3}{20}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{3}{20}$

Therefore,

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}$

Question # 2

Answer:

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}$

Step-by-step explanation:

Given

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}$

$=-\frac{6}{35}-\frac{1}{6}\times \frac{3}{2}\times \frac{2}{5}\times \frac{1}{14}$ ∵ $\frac{2}{5}\times \frac{-3}{7}=-\frac{6}{35}$

$=-\frac{6}{35}-\frac{1}{140}$ ∵ $\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=\frac{1}{140}$

$\mathrm{Least\:Common\:Multiplier\:of\:}35,\:140:\quad 140$

$=-\frac{24}{140}-\frac{1}{140}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-24-1}{140}$

$\mathrm{Subtract\:the\:numbers:}\:-24-1=-25$

$=\frac{-25}{140}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{25}{140}$

$\mathrm{Cancel\:the\:common\:factor:}\:5$

$=-\frac{5}{28}$

Therefore,

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}$

4 0

4 years ago

12 + 4x > 24 or 10 - 12x > 22

Wewaii [24]

Answer:

10 - 12 × > 22 Yan Yong sagot

8 0

3 years ago