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goldfiish [28.3K]
3 years ago
5

Use a graphing calculator to estimate the local maximum and local minimum values of the function to the nearest hundreth.

Mathematics
1 answer:
user100 [1]3 years ago
6 0

Answer:

max is at (-.49, 3.63)

min is at (1.37, -6.01)

Step-by-step explanation:

When you get into calculus, this will be way easier to figure analytically, but I'm guessing you're in Algebra 2 since I taught it this way to my Algebra 2 students.  Calculus is easier than this.

Use your calculator to graph the function.  Once it is graphed, hit "2nd" then "trace" then "maximum" which is usually #4.  You will see a blinking cursor somewhere on the curve.  Use the arrow buttons to move the cursor JUST over the max point and to the immediate left of it.  Hit "enter".  Then use the other arrow button to move the cursor again JUST over the max to the immediate right of it and hit enter again.  Hit "enter" one more time and you will see the word "Maximum" and the x and y values of that max point.  From that screen, again hit "2nd" then "trace" then "minimum" which is usually #3.  Do the same again with the cursor and the buttons and you'll get the min values.

Again, calculus is way easier for finding max and min values and where the function increases and decreases, but you'll have to wait a bit.

Either way, learn how your calculator works...it does WAY WAY more than you'd ever think imaginable!

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mestny [16]
A) 6.5
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4 0
3 years ago
Please help me !!!!!!!!!
lidiya [134]

Answer:

f(-2) = 0

f(1) = 12

f(2) = 5

Step-by-step explanation:

f(-2) will lie in the function f(x) =x^2 - 4

\therefore f( - 2) =  {( - 2)}^{2}  - 4 = 4 - 4 = 0

f(1) will lie in the function f(x) =2x^2 +10

\therefore f(1) = 2 {(1)}^{2}  + 10 = 2 + 10 = 12

f(2) will lie in the function f(x) =5

\therefore f(2) = 5

5 0
3 years ago
What is the lcm of 32 and 45
Talja [164]
1440 will be your least common multiple
7 0
3 years ago
Read 2 more answers
An envelope with 96 bookmarks in it has a mass of 1467 grams. The same envelope with 49 bookmarks in it has a mass of 762 grams.
masya89 [10]

If m is the mass of the envelope and b the mass of one bookmark, then

\begin{cases}m+96b=1467\\m+49b=762\end{cases}

We have

(m+96b)-(m+49b)=1467-762\implies47b=705\implies b=15

Then

m+96\cdot15=1467\implies m+1440=1467\implies m=27

so the envelope has a mass of 27 grams.

8 0
4 years ago
Yeaaaaaaaaaa help plzzzzzzzzzz
Tju [1.3M]

Answer:

See Explanation

Step-by-step explanation:

Given

The attached graph

Required

Point on the line

The options are not given. So, I will provide general answers.

To do this, we simply write out the coordinates that lie on the line.

Some of them are:

(0.5,3)

(1.25,8)

(1.5,10)

8 0
3 years ago
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