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algol13
2 years ago
15

The square of the sum of two consecutive positive even integers is greater than the sum of their squares by 48. Find the two int

egers.​
Mathematics
1 answer:
koban [17]2 years ago
3 0

Answer:

  • 4 and 6 or -6 and -4

Step-by-step explanation:

Let the numbers are 2x and 2x + 2.

<u>We have:</u>

  • (2x + 2x + 2)² = (2x)² + (2x + 2)² + 48
  • 4(2x + 1)² = 4x² + 4(x + 1)² + 48
  • (2x + 1)² = x² + (x + 1)² + 12
  • 4x² + 4x + 1 = x² + x² + 2x + 1 + 12
  • 2x² + 2x - 12 = 0
  • x² + x - 6 = 0
  • (x - 2)(x + 3) = 0
  • x = 2, x = -3

<u>The numbers are:</u>

  • 4 and 6 or - 6 and - 4

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Answer:

x = 41°

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Step-by-step explanation:

If angles 1 & 2 are supplementary, that means...

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To find the value of each angle, you first must find the value of x by plugging in the values of both angles...

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First, combine like values, then subtract add 25 to both sides.

3x + 2x = 5x\Longrightarrow 5x - 25+ (25) = 180 + (25)\\\\5x=205

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\frac{5x = 205}{5}\\\\x = 41\textdegree\\\\\angle1= 3x = 3(41) = 123\textdegree\\\\\angle2=2x-25=2(41)-25=82-25=57\textdegree

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