The square of the sum of two consecutive positive even integers is greater than the sum of their squares by 48. Find the two int
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Answer:
x = 10
Step-by-step explanation:
Using the rules of logarithms
• log x + log y ⇔ log(xy)
• log ⇔ n log x
• log x = log y ⇒ x = y
Given
ln20 + ln5 = 2 lnx , then
ln(20 × 5) = ln
ln 100 = ln, hence
x² = 100 ( take the square root of both sides )
x = 10
<h3>Solution:</h3>
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