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Sati [7]
3 years ago
10

Evaluate 1/3 x 14/21

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

2/9.

Step-by-step explanation:

Perform multiplication across the fractions. C'mon.

iogann1982 [59]3 years ago
5 0

Answer:14/7 which equals2

Step-by-step explanation:

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The sum of two numbers is fifteen. The product of the two numbers is thirty six. Find the numbers
Diano4ka-milaya [45]
Best to take this in two parts. 

1, find the factors of 36:
1 and 36
2 and 18
3 and 12
4 and 9
6 and 6

2, Now, using those, add the factors and see which add up to 15... in this case, that would be 12 and 3!
4 0
4 years ago
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I need help with this ^
VLD [36.1K]

Answer:

i think 13

Step-by-step explanation:

60+57=117

117/9=13

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3 years ago
Find the area and perimeter of an isosceles trapezoid with legs 25cm and bases 16cm and 30cm
Varvara68 [4.7K]
<u>A=1/2h(b1+b2)</u>
= 1/2(h)(30+16)
<em>>how to find h<</em>
<em>>30-16= 14/2 = 7<</em>
<em>>25²-7² = 625-49 = 576<</em>
<em>>√576 = 24 .. h=24<</em>
= 1/2(24)(30+16)
= 12(46)
A = 552 cm²
<u>P= b+b+l+l</u>
= 30+16+25+25
P = 96 cm
4 0
4 years ago
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One stick of butter contains 91.6g of fat. Convert this to milligrams.
Leni [432]

Answer:

91600 milligrams

Step-by-step explanation:

1 gram = 1000 milligrams

4 0
3 years ago
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Find the sum of the convergent series by using a well-known function. (Round your answer to four decimal places.) [infinity] (−1
Mashutka [201]

Answer:

Here is the full question:

Find the sum of the convergent series by using a well-known function. (Round your answer to four decimal places.) Σ_(n=1)^∞ (-1)^n+1 1/7^n n

Step-by-step explanation:

Σ_(n=1)^∞ (-1)^n+1 1/7^n n

We will use the function In (1 + x)

We will now give a power series expansion of the function while it is centered at x=0

This will give us In (1 + x) = Σ_(n=1)^∞(-1)^{n+1}\frac{x^{n} }{n}

Note that x= 1/7

Now let us equate the two equations

Σ_(n=1)^∞(-1)^{n+1}\frac{1}{7^{n}n } = ㏑(1 + x)|_{x = \frac{1}{7} } = ㏑\frac{8}{7}

Sum of the series will give ㏑\frac{8}{7}

4 0
4 years ago
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