We know that
Perimeter=2AB+2AD=34 in-----> AB+AD=17-----> AB=17-AD-----> equation 1
MA=MD
MA²=AB²+(AD/2)²
for the triangle AMD
AD²=[MA²+MD²]----> AD²=2*[MA²]----> AD²=2*[AB²+(AD/2)²]---> equation 2
I substitute 1 in 2
AD²=2*[(17-AD)²+(AD/2)²]----> AD²=2*[289-34AD+AD²+0.25AD²]
AD²=578-68AD+2.50AD²--------> 1.50AD²-68AD+578
1.50AD²-68AD+578=0
using a graph tool to solve the quadratic equation
see the attached figure
AD1=11.33 in
AD2=34 in----------is not solution because (AB+AD=17)
Solution is AD=11.33 in
AB=17-11.33--------> 17-11.33-----> AB=5.67 in
the answer is
AD=11.33 in
<span>AB=5.67 in</span>
Answer:
10
2
Step-by-step explanation:
if x=0 => y = 2(0)+10= 10
y = mx + c
m = slope factor
=> y = 2x + 10
so, slope factor = 2
Answer:
The volume of the larger pyramid is equal to 
Step-by-step explanation:
step 1
Find the scale factor
we know that
If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor
Let
z----> the scale factor
In this problem, the ratio of the height is equal to the scale factor
step 2
Find the volume of the larger pyramid
we know that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z----> the scale factor
x----> volume of the smaller pyramid
y----> volume of the larger pyramid
we have
substitute
The area of a regular hexagon with an apothem 18.5 inches long and a side 21 inches is 1, 165. 5 In²
<h3>
How to calculate the area of a regular hexagon</h3>
The formula is given thus;
Area of hexagon = (1/2) × a × P
where a = the length of the apothem
P = perimeter of the hexagon
Given a = 18. 5 inches
Note that Perimeter, p = 6a with 'a' as side
p = 6 × 21 = 126 inches
Substitute values into the formula
Area, A = 1 ÷2 × 18. 5 × 126 = 1 ÷2 × 2331 = 1, 165. 5 In²
Thus, the area of the regular hexagon is 1, 165. 5 In²
Learn more about the area of a hexagon here:
brainly.com/question/15424654
#SPJ1
Answer:
X could be 2, 3, 4, 5, 6, 7, 8, or 9.
So, your final answer could be either 52, 53, 54, 55, 56, 57, 58, or 59.
