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Sav [38]
3 years ago
12

My rectangular soccer field site has a length equal to one and a half times it’s width. Find the area of its length x.

Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

Let width = x

Let length = 1.5x

Area = (length)(width)

Area = 1.5x2

Step-by-step explanation:

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Write an equivalent expression by distributing the " sign outside the parentheses: 5n - (7.4p - 9.6​
liberstina [14]
5n - 7.4p + 9.6 is the answe
4 0
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How many solutions do these equations have y= 3x+4 y+6=3x
Nataly [62]

Answer:

Step-by-step explanation:

hello :

the system is :  y= 3x+4....(*)

                         y+6=3x....(**)

by (**) : y = 3x - 6

so : y= 3x+4

      y= 3x - 6

means :  3x+4 = 3x - 6

                     4= -6.......(false)

conclusion : no reals  solutions

5 0
3 years ago
What value of x will give the minimum value of 2x^2 - 12x + 3?
Vera_Pavlovna [14]

Answer:

Answer:

=2x2−12x+3

or

0,3

Step-by-step explanation:

Hope I helped

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6 0
3 years ago
Read 2 more answers
Please solve w work. 4(610−15)+0.4
Ivenika [448]
4(610-15)+0.4
first you have to distribute the 4 to what is inside the paranthesis
(4×610)-(4×15)+0.4
2440-60+0.4=2380.4
8 0
3 years ago
Perform the following operations and write the answers in radical form.
strojnjashka [21]

Given:

Part A: \sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}

Part B: 3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}

To find:

The simplified radical form.

Solution:

Part A: \sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}

\sqrt{98}=\sqrt{7^2 \times 2} =7 \sqrt{2}

\sqrt{18}=\sqrt{3^2 \times 2} =3 \sqrt{2}

Substitute these in the given expression.

\sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}=\sqrt{7}+\sqrt{3}+7\sqrt{ 2}-3\sqrt{ 2}

Add or subtract the coefficient of same radical.

                                    =\sqrt{7}+\sqrt{3}+(7-3)\sqrt{ 2}

                                    =\sqrt{7}+\sqrt{3}+4\sqrt{ 2}

Part B: 3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}

2 \sqrt{121}=2\sqrt{11^2}

           =2\times 11

           = 22

3 \sqrt{90}=3\sqrt{3^2 \times 10}

           =3\times 3 \sqrt{10}

           =9 \sqrt{10}

Substitute these in the given expression.

3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}=3 \sqrt{5}-3 \sqrt{11}+22-9 \sqrt{10}

8 0
3 years ago
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