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3 years ago

X+2y=16 standard to slope intercept simplification

Mathematics

1 answer:

DIA [1.3K]3 years ago

7 0

Y = (-x + 16)/2

explanation:
x+2y = 16
-x -x
2y = -x + 16
(divide by 2 on bo sides to get y alone)

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Aaron is 6 years old, Beth is 9 years old and Charlie is 15 years old. They are going to share £5940 in the same ratio as their

Andre45 [30]

Answer:

$Aaron=1188$

$Beth=1782$

$Charlie=2970$

Step-by-step explanation:

From the question we are told that

Ratio 6:9:15

Total amount to e shared N=£5940

Generally the Ratio can divide the Total amount mathematically as follows

Ratio

6:9:15/3=2:3:5

Sum of ratio

2+3+5=10

For Aaron

$A=\frac{2}{10} *5940$

$A=1188$

For Beth

$B=\frac{3}{10} *5940$

$B=1782$

For Charlie

$C=\frac{2}{10} *5940$

$C=2970$

Check answer

$A+B+C=5940\\1188+1782+2970=5940$

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2 years ago

N 4(x + 2) + 50y + 3). An equivalent expression is Reset Next

natita [175]

Answer:

4x+50y+11

hope this helps :) plz brainliest

Step-by-step explanation:

7 0

3 years ago

What is the slope of the line passing through the points ( −3 , 4 ) and ( 4, −1 )?

ziro4ka [17]

Slope = (y2 - y1)/(x2 - x1) = (-1 - 4)/(4 - (-3)) = -5/(4 + 3) = -5/7

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3 years ago

Which of the following is equivalent to 7-2( x + 2) <-4 - 3(1 – x)?

suter [353]

The answer is (A) you because the equation is equal to X>2 and answer A is also equal to X>2

6 0

3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0

3 years ago