Answer:
see the attachment photo!
Midsegment = 1/2(base1 + base2)
EF = 1/2(AB + CD)
EF = 1/2(20 + 12)
EF = 1/2(32)
EF = 16
Answer
EF = 16
Answer:
1 is Answer.
Step-by-step explanation

= 
As we know that ω²+ω+1=0
Thus putting in above equation, we get
= 
Rearranging and simplifying:
= 
= 
= 
= 1 Answer
Good question , don’t really know but use photo math or there’s an link for you