Given:
The ratio and rates:
1. 30 ft. To 60.Ft
2. 51 males to 21 females
3. 1,500 meters in 6 seconds
4. $36 for 4 rounds of shrimp
To find:
The fraction in simple terms for the given ratio and rates.
Solution:
1. 30 ft. To 60.Ft
2. 51 males to 21 females
3. 1,500 meters in 6 seconds
4. $36 for 4 rounds of shrimp
Answer:
I believe it's 42
Step-by-step explanation:
Replace each letter in the expression with the assigned value.
First, replace each letter in the expression with the value that has been assigned to it. To make your calculations clear and avoid mistakes, always enclose the numbers you're substituting inside parentheses. The value that's given to a variable stays the same throughout the entire problem, even if the letter occurs more than once in the expression.
However, since variables "vary", the value assigned to a particular variable can change from problem to problem, just not within a single problem.
Perform the operations in the expression using the correct order of operations.
Once you've substituted the value for the letter, do the operations to find the value of the expression.
Answer:
There is only one distinct triangle possible, with m∠N ≈ 33°. i hope this helps :)
Step-by-step explanation:
In △MNO, m = 20, n = 14, and m∠M = 51°. How many distinct triangles can be formed given these measurements?
There are no triangles possible.
There is only one distinct triangle possible, with m∠N ≈ 33°.
There is only one distinct triangle possible, with m∠N ≈ 147°.
There are two distinct triangles possible, with m∠N ≈ 33° or m∠N ≈ 147°.
Answer:
Sorry I don’t know I’m just answering this to so I can answer mine I’m sorry
Step-by-step explanation:
:<
Answer:
Check below, please
Step-by-step explanation:
Step-by-step explanation:
1.For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.)
When the derivative of a function is equal to zero, then it occurs when we have either a local minimum or a local maximum point. So for our x-coordinates we can say
2. For which values of x is f '(x) positive?
Whenever we have
then function is increasing. Since if we could start tracing tangent lines over that graph, those tangent lines would point up.
3. For which values of x is f '(x) negative?
On the other hand, every time the function is decreasing its derivative would be negative. The opposite case of the previous explanation. So
4.What do these values mean?
5.(b) For which values of x is f ''(x) zero?
In its inflection points, i.e. when the concavity of the curve changes. Since the function was not provided. There's no way to be precise, but roughly
at x=-4 and x=4
