The graph of 3x - 2y = 6 does not pass through (4, -3) (-2, -6)
2 answers:
In order to solve the True or False problem we have to actually graph the problem (3x-2y=6).
As we can tell the slope is 3/2 and the Y-Intercept is -3
Here is the graph:
As we can tell the slope is 3/2 and the Y-Intercept is -3
Here is the graph:
Answer:
The graph of does not pass through (4,-3)
Step-by-step explanation:
We have the expression we have to see if the points
and
pass through the graph of the expression.
Then we have to replace the points in the equation.
A=(4,-3)
We can see that the equation is not verified when we replace the point A=(4,-3) in the expression. This means that the graph of doesn't pass through the point A.
B=(-2,-6)
We can see that the equation is verified when we replace the point B=(-2,-6) in the expression. This means that the graph of pass through the point B.
We can see the graph of the function:
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Answer:
a) Null hypothesis:
Alternative hypothesis:
b) the test statistics is : 2.15
c) The p-value is 0.0158
d) NO, there is evidence that the mean time of telephone survey is less than 15 and premium rate is not justified.
Step-by-step explanation:
The data in the Microsoft Excel are:
17;11;12;23;20;23;15;
16;23;22;18;23;25;14;
12;12;20;18;12;19;11;
11;20;21;11;18;14;13;
13;19; 16;10;22;18;23.
a) Formulate the null and alternative hypotheses for this application.
From the question, Fowle Marketing Research Inc. is taking base charge from a client on the given assumption that if the mean time of telephone survey is 15 minutes or less.
The null and alternative hypotheses are therefore as follows:
Null hypothesis:
The null hypothesis states that there is evidence that the mean time of telephone survey is less than 15 and premium rate is not justified.
Alternative hypothesis:
The alternative hypothesis states that there is evidence that the mean time of telephone survey exceeds 15 and premium rate is justified.
b) Compute the value of the test statistic.
Given that:
n = 35
The sample mean is;
Thus:
Thus; the test statistics is : 2.15
c) What is the p-value?
p-value = P(Z > 2.15)
p-value = 1 - P(Z ≤ 2.15)
From the standard normal table, the value of P(Z ≤ 2.15) is 0.9842
p-value = 1 - 0.9842
p-value = 0.0158
The p-value is 0.0158
d) At a = .01, what is your conclusion?
According to the rejection rule, if p-value is less than 0.01 then reject null hypothesis at ∝ = 0.01
Thus; p-value = 0.0158 > ∝ = 0.01
By the rejection rule, accept the null hypothesis.
Therefore, there is evidence that the mean time of telephone survey is less than 15 and premium rate is not justified.