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ra1l [238]
3 years ago
11

Natalie and Preston would like to accumulate $25,000 at the end of 3.5 years for a future down payment on a house in Prescott. H

ow much should they deposit at the end of each week in a savings account that pays 7.2%/a compounded monthly to meet their goals?
Mathematics
1 answer:
Brrunno [24]3 years ago
3 0

Answer:

$7.4 should be deposited at the end of each week

Step-by-step explanation:

In this question, we are asked to calculate the principal amount that should be deposited to get a house of $25,000 at the interest and time given in the question

To solve this problem, we use the compound interest formula.

Mathematically;

A = P(1+ r/n) ^ nt

From the question, we identify the following;

A is the amount that is targeted which is the principal plus the targeted interest = $25,000 according to the question

P is the amount invested at the beginning which we are looking for

r is the rate which is 7.2% = 7.2/100 = 0.072

n is the number of times we compound per year which is 12 times( compounding is per month)

t is the number of years which is 3.5 years

To get the principal, we can rewrite the equation to be;

A/(1+r/n)^nt = P

25,000/(1 + 0.072/12)^(12 * 3.5) = P

P = 25,000/18.54 = $1,348

But the question asks how much to be deposited at the end of each week

The number of weeks in 3.5 years is 3.5 * 52 =182 weeks

Thus, the amount deposited at the end of each week will be 1,348/182 = $7.4

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Answer:

Step-by-step explanation:

Call T the top

call G the bottom

T G B is a right triangle

37 at B, 90 at G, thus 53 at BTG

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25 at A, 90 at G, thus 65 at ATG

thus 122 at ABT

law of sines:

sin 25 / BT = sin 12/ 57

so BT = 156 meters (first answer)

now angle ABT = 180 - 12 - 25

= 143

so

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4 0
2 years ago
During the day,Sam spent $4.85 on lunch.he also bought 2 books for $7.95 each. At the end of the day we had $8.20 left how much
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7 0
3 years ago
Answer correclty PLZZZ
ioda

Answer: option C is the correct answer

Step-by-step explanation:

The system of linear equations is

10x + 7y = 12 - - - - - - - 1

8x + 7y = 18 - - - - - - - 2

Since the coefficient of y is the same in equation 1 and equation 2, we will eliminate y by subtracting equation 2 from equation 1, it becomes

10x - 8x + 7y - 7y = 12 - 18

2x = -6

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Let the constants be on the right hand side and the term containing y be on the left hand side. It becomes

7y = 12 + 30

7y = 42

y = 42/7

y = 6

C) (−3, 6)

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