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2 years ago

My last question please help I keep getting it wrong!!

Mathematics

2 answers:

Romashka-Z-Leto [24]2 years ago

6 0

1. Divide by 4
sqrt 2x+8 = 6

2. Square both sides to remove square root
2x+8 = 36

3. Subtract 8
2x = 28

4. Divide by 2 to make x by itself
x = 14

OLga [1]2 years ago

4 0

Answer:

$4 \sqrt{2(2) + 8} = 4 \sqrt{4 + 8 } = 4 \sqrt{12} = 4(6) = 24$

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s2008m [1.1K]

Answer:

Solid dot on -7 with the line going to the right towards 0

Step-by-step explanation:

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2 years ago

Solve (x+y) if x=-1/2 and y=-3

bixtya [17]

Answer:

$-3\frac{1}{2}$

Step-by-step explanation:

Solve

$(x+y)$

For x=-1/2 and y=-3

substitute the value of x and the value of y in the expression above

$x+y=(-\frac{1}{2})+(-3)$

Remember that

$(+1)(-1)=-1$

$x+y=-\frac{1}{2}-3=\frac{-1-6}{2}=-\frac{7}{2}$

Convert to mixed number

$-\frac{7}{2}=-\frac{6}{2}-\frac{1}{2}=-3\frac{1}{2}$

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3 years ago

The sum of two positive numbers is 588. minimize the sum of the first and three times the second

Marianna [84]

9514 1404 393

Answer:

{587, 1}

Step-by-step explanation:

The sum will be minimized when the second number is as close to zero as is allowed. If the numbers must be positive integers, the sum is minimized when the numbers are {587, 1}.

If the numbers may be real numbers, then the values that minimize the sum are {588-, 0+}

_____

The "cost" of taking a unit from the sum 588 and assigning it to the second number is that the sum of first and 3 times the second goes up by 3. In order to minimize that sum, the second number must be minimized.

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2 years ago

1f f(x) = ***, g(x) = x+4, and h(x) - 3x-2, what is (nofog)(x)?

Stels [109]

Answer:

first option y + 7 = –(x + 6) is correct option

Step-by-step explanation:

7 0

2 years ago

Verify that the following function is a probability mass function, and determine the requested probabilities. f left-parenthesis

Licemer1 [7]

Answer:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

Step-by-step explanation:

For this case we have the following density function:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

7 0

2 years ago

My last question please help I keep getting it wrong!!​

My last question please help I keep getting it wrong!!