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777dan777 [17]
4 years ago
9

What statement is true about the part of the electromagnetic spectrum that is visible to the human eye?

Physics
2 answers:
nekit [7.7K]4 years ago
8 0

For future peeps the answer is D. It is divided into seven ranges of wavelengths.

I just took the test and it is correct. Just a heads up I got an A on my test so...

Alja [10]4 years ago
7 0
Based on the options above, I see how the last option would actually be most fitting to how "the part of the electromagnetic spectrum that is visible to the human eye". This would be in separate parts, which would be divided into a certain number, which would actually be only 7 ranges of wavelengths. And therefore, this last statement would actually go very well and it would actually be the correct answer. And this would all relate to how <span> the part of the electromagnetic spectrum that is visible to the human eye, it's based on it's own 7 division parts that it has. 

Your answer: </span>\textsf{It is divided into seven ranges of wavelengths}
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An element had 82 protons, 83 neutrons, and 82 electrons. What is the symbol of the element
serg [7]
Name: Lead
Symbol: Pb
Atomic Number: 82
Atomic Mass: 207.2 amu
Melting Point: 327.5 °C (600.65 K, 621.5 °F)
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3 years ago
Two particles with charges of 5.00 μ C and -3.00 μC are placed 0.250 m apart. Where can a third charge be placed so that the net
MAXImum [283]

Answer:

0.86 m

Explanation:

q₁ = magnitude of positive charge = 5 x 10⁻⁶ C

q₂ = magnitude of negative charge = 3 x 10⁻⁶ C

r = distance between the two charges = 0.250 m

d = distance of the location of third charge from negative charge

q = magnitude of charge on third charge

Using equilibrium of electric force on third charge

\frac{kq_{2}q}{d^{2}} = \frac{kq_{1}q}{(r+d)^{2}}

\frac{q_{2}}{d^{2}} = \frac{q_{1}}{(r+d)^{2}}

\frac{(5\times 10^{-6})}{(0.250+d)^{2}} = \frac{(3\times 10^{-6})}{(d^{2}}

d = 0.86 m

4 0
3 years ago
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kkurt [141]

Explanation:

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(it’s .5555555555)

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