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Answer:
E = 0 r <R₁
Explanation:
If we use Gauss's law
Ф = ∫ E. dA =
/ ε₀
in this case the charge is distributed throughout the spherical shell and as we are asked for the field for a radius smaller than the radius of the spherical shell, therefore, THERE ARE NO CHARGES INSIDE this surface.
Consequently by Gauss's law the electric field is ZERO
E = 0 r <R₁
The Cell Membrane is what controls what enters and leaves the cell.
Answer:
The induced current direction as viewed is clockwise
Explanation:
Lenz's Law states that the induced e. m. f. causes current to be driven in the loop of wire in such a way as to generate magnetic field that are oppose the magnetic flux change which is the source of the induced current
Therefore, as the magnet approaches the coil with the south pole, the coil produces current equivalent to the upward movement of the south pole of a permanent magnet through it which according to Flemings Right Hand Rule is clockwise
Therefore;
The direction of the induced current in the loop (as viewed from above, looking down the magnet) is clockwise
Answer: +2.10V
Explanation:

Using Nernst equation :

![E_{cell}=E^o_{cell}-\frac{0.059}{n}\log [Al^{3+}]^2\times [I^-]^6](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.059%7D%7Bn%7D%5Clog%20%5BAl%5E%7B3%2B%7D%5D%5E2%5Ctimes%20%5BI%5E-%5D%5E6)
where,
= standard emf for the cell = +2.20 V
n = number of electrons in oxidation-reduction reaction = 6
= emf of the cell = ?
= concentration = 
= concentration = 
Now put all the given values in the above equation, we get:
![E_{cell}=+2.20-\frac{0.059}{6}\log [5.0\times 10^{-3}]^2\times [0.10]^6](https://tex.z-dn.net/?f=E_%7Bcell%7D%3D%2B2.20-%5Cfrac%7B0.059%7D%7B6%7D%5Clog%20%5B5.0%5Ctimes%2010%5E%7B-3%7D%5D%5E2%5Ctimes%20%5B0.10%5D%5E6)

The standard emf for the cell using the overall cell reaction below is +2.10 V