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sergiy2304 [10]
3 years ago
9

Speed of light in air is 3 x 10 m/s, determine the speed of light in the glass fibre.

Physics
1 answer:
Dafna11 [192]3 years ago
4 0
30 speed of light in the glass
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A 100 kg mass is pulled along a frictionless surface by a horizontal force F such that its acceleration is 8.0 m/s2. A 20 kg mas
nadya68 [22]

Answer:

a) 60 N

b) 860 N

Explanation:

Given that,

m_1 = 100 kg

m_2 = 20 kg

a_{1} = 8.0 \frac{m}{s^{2}}

a_{2} = 3.0 \frac{m}{s^{2}}

a) By Newton's Law,

∑F_{m_2,x} = f_k = m_{2} * a_{2}

∑F_{m_2,y} = F_{N} - m_{2} * g = 0

Hence,

f_k = m_2 * a_2 = 20 * 3 = 60 N

b) By Newton's Law

∑F_{m_1,x} = F = m_{1} * a_{1}

Hence,

F = m_{1} * a_{1} = 100 * 8 = 800 N

Net force acting on 100 kg mass,

F_{net} = F + f_k = 800 + 60 = 860 N

6 0
3 years ago
Can someone please help me with some physics​
Dimas [21]

Answer:

sure I will helpy you iru

6 0
3 years ago
The following equation is an example of decay?<br><br> 232/90 TH---4/2 HE +228/88 RA?
DaniilM [7]

Answer:

Alpha decay

Explanation:

  • Alpha decay is one of the three major types of decays, others being, beta decay and gamma decay.
  • <em><u>When a radioactive isotope undergoes alpha decay it emits alpha particles. An alpha particle is equivalent to the nucleus of Helium atom.</u></em>
  • <em><u>Therefore, an atom undergoing decay, its atomic mass is decreased by 4 and its atomic number is decreased by 2. </u></em>
  • Thus, since 232/90 Th, has undergone alpha decay its mass number is reduced by 4 to 228 and its atomic number by 2 to 88, and becomes 228/88 Ra.
5 0
3 years ago
1:
Ksenya-84 [330]

Answer:

Bowl will have maximum potential energy

Explanation:

It is the bowl that will have maximum potential energy.

It is because potential energy is high when both height and mass of the object is high.

Here in this case the bowl has maximum weight with maximum height except the tea cup but the potential weight of cup will not make much impact as its weight is very low.

6 0
3 years ago
A space vehicle is traveling at 2980 km/h relative to Earth when the exhausted rocket motor is disengaged and sent backward. The
Strike441 [17]

Answer:

3054.4 km/h

Explanation:

Using the conservation of momentum

momentum before separation = 5M × 2980 Km/h where M represent the mass of the module while 4 M represent the mass of the motor

initial momentum = 14900 M km/h

let v be the new speed of the motor so that the

new momentum = 4Mv and the new momentum of the module  = M ( v + 94 km/h )

total momentum = 4Mv + Mv + 93 M = 5 Mv + 93M

initial momentum = final momentum

14900 M km/h = 5 Mv + 93M

14900 km/h = 5v + 93

14900 - 93 = 5v

v = 2961.4 km/h

the speed of the module = 2961.4 + 93 = 3054.4 km/h

8 0
3 years ago
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