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Rzqust [24]
2 years ago
13

A ball with a volume of 3 cm3 and a density of 9.0 g/cm3 increases its velocity from 2 m/s to 6 m/s over a 12

Physics
1 answer:
V125BC [204]2 years ago
4 0

Answer:

M = ρ V = 9 gm/cm^ 3 * cm^3 = 27 gm

a = (V2 - V1) / t = (6 - 2) m/s / 12 s = 1/3 m/s^2     the acceleration

F = M a = 27 gm * 1/3 m/s^2 = 9 dynes      net force applied

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A mass weighing pounds is attached to a spring whose constant is lb/ft. The medium offers a damping force that is numerically eq
andreyandreev [35.5K]

Answer:

hello your question has some missing values attached below is the complete question with the missing values

answer :

a) 0.083 secs

b) 0.33 secs

c)  3e^-4/3

Explanation:

Given that

g = 32 ft/s^2 ,  spring constant ( k ) = 2 Ib/ft

initial displacement = 1 ft above equilibrium

mass = weight / g = 4/32 = 1/8

damping force = instanteous velocity  hence  β = 1

a<u>)Calculate the time at which the mass passes through the equilibrium position.</u>

time mass passes through equilibrium = 1/12 seconds = 0.083

<u>b) Calculate the time at which the mass attains its extreme displacement </u>

time when mass attains extreme displacement = 1/3 seconds = 0.33 secs

<u>c) What is the position of the mass at this instant</u>

position = 3e^-4/3

attached below is the detailed solution to the given problem

6 0
2 years ago
Blake stands in a canoe in the middle of a lake. The canoe is stationary. Blake holds an anchor mass of 15 kg, then throws it we
Inessa05 [86]

The velocity of the canoe is  1.7 m/s.

<h3>What is momentum?</h3>

Momentum in physics is the products of mass and velocity. Now we have to find momentum with the formula; p = mv

a) Initial momentum = (15)8 m/s + 135 = 255 Kgms-1

b) Since momentum is conserved, the total momentum after throwing the anchor is still 255 Kgms-1

c) The final velocity of the boat is obtained from;

255 Kgms-1 = (15Kg + 135 Kg) v

v = 255 Kgms-1/(15Kg + 135 Kg)

v = 1.7 m/s

Learn more about momentum: brainly.com/question/904448

5 0
2 years ago
What is speed of light in crown glass?
german

Answer:

1.97 x 10^8 m/s

Explanation:

refractive index of crown glass with respect to air, n = 1.52

speed of light in air, c = 3 x 10^8 m/s

Let v be the speed of light in crown glass.

By use of the definition of refractive index

n = \frac{c}{v}

where, n be the refractive index of crown glass, c be the speed of light in vacuum and v be the speed of light in crown glass

1.52 = \frac{3 \times 10^{8}}{v}

v = \frac{3 \times 10^{8}}{1.52}

v = 1.97 x 10^8 m/s

Thus, the speed of light in crown glass is 1.97 x 10^8 m/s.

5 0
2 years ago
I NEED HELP PLEASE, thanks! :)
topjm [15]

Answer:

2.96×10⁸ m/s

Explanation:

Speed = distance / time

v = (2 × 3.85×10⁸ m) / (2.60 s)

v = 2.96×10⁸ m/s

6 0
3 years ago
A 20-N falling object encounters 4 N of air resistance. The magnitude of the net force on the object is?
Irina18 [472]

16-N because 20-4=16

8 0
2 years ago
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