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Zigmanuir [339]
3 years ago
13

Question 37 the answer is about x=5.25 can someone please explain to me how to do that problem without a calculator also questio

n 39 there is supposed to be two answers I found .52 but the other one is x=2.26 and idk how to get that one and again no calculator

Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer:

37) m∠x = 5.25

39) m∠x = 0.5236 and m∠x = 2.62

Step-by-step explanation:

37)

∵ cotx = -0.6 and 3π/2 ≤ x ≤ 2π

∴ tanx = -1/0.6

∵ ∠ x in the fourth quadrant ⇒ ∴ m∠x = 2π - α where α is an acute angle

∵ tanα = 1/0.6 ⇒ α = tan^{-1}\frac{1}{0.6}

∴ α = 1.03038

∴ m∠x = 2π - 1.03038 = 5.25

39)

∵ cscx = 2 and 0 ≤ x ≤ 2π

∴ sinx = 1/2 ⇒ +ve value

∴ ∠x is in the first quadrant or the second quadrant

∴ m∠x = α or m∠x = π - α

∵ sinα = 1/2 ⇒ ∴ α = sin^{-1}\frac{1}{2}

∴ α = 0.5236

∴ m∠x = 0.5236

∴ m∠x = π - 0.5236 = 2.6216 ≅ 2.62

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Match each function to its corresponding sequence.
givi [52]

The sequence and their functions are:

  • f(n) = f(n - 1) + 7 ⇒ 3, 10, 17, 24, 31.....
  • f(n) = f(n - 1) + 4n - 2 ⇒ 3, 9, 19, 33, 51.....
  • f(n) = 2[f(n - 1)] ⇒ 3, 6, 12, 24, 48.....

<h3>How to match the functions?</h3>

To do this, we simply set values for n and calculate the function values using the current value of n.

So, we have:

<u>Function 1: f(n) = f(n - 1) + 6n - 5 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 6(2) - 5 = 3 + 12 - 5 = 10

Let n = 3

f(3) = f(2) + 6(3) - 5 = 10 + 18 - 5 = 23

None of the sequence follows the pattern 3, 10, 23....

<u>Function 2: f(n) = f(n - 1) + 2n - 1 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 2(2) - 1 = 3 + 4 - 1 = 6

Let n = 3

f(3) = f(2) + 2(3) - 1 = 6 + 6 - 1 = 11

None of the sequence follows the pattern 3, 6, 11....

<u>Function 3: f(n) = f(n - 1) + 6 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 6 = 3 + 6 = 9

Let n = 3

f(3) = f(2) + 6 = 9 + 6 = 15

None of the sequence follows the pattern 3, 9, 15....

<u>Function 4: f(n) = f(n - 1) + 7 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 7 = 3 + 7 = 10

Let n = 3, 4 and 5

f(3) = f(2) + 7 = 10 + 7 = 17

f(4) = f(3) + 7 = 17 + 7 = 24

f(5) = f(4) + 7 = 24 + 7 = 31

So, we have:

f(n) = f(n - 1) + 7 ⇒ 3, 10, 17, 24, 31.....

<u>Function 5: f(n) = f(n - 1) + 4n - 2 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 4(2) - 2 = 3 + 8 - 2 = 9

Let n = 3, 4 and 5

f(3) = f(2) + 4(3) - 2 = 9 + 12 - 2 = 19

f(4) = f(3) + 4(4) - 2 = 19 + 16 - 2 = 33

f(5) = f(4) + 4(5) - 2 = 33 + 20 - 2 = 51

So, we have:

f(n) = f(n - 1) + 4n - 2 ⇒ 3, 9, 19, 33, 51.....

<u>Function 6: f(n) = 2[f(n - 1)] where f(1) = 3</u>

Let n = 2

f(2) = 2 * f(1) = 2 * 3 = 6

Let n = 3, 4 and 5

f(3) = 2 * f(2) = 2 * 6 = 12

f(4) = 2 * f(3) = 2 * 12 = 24

f(5) = 2 * f(4) = 2 * 24 = 48

So, we have:

f(n) = 2[f(n - 1)] ⇒ 3, 6, 12, 24, 48.....

Read more about sequence at:

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2 years ago
HELP ASAP PLZ 39 POINTS<br> Find x, y, u, v
Ad libitum [116K]

Answer:

x = 9; y = 12; u = 24; v = 32

Step-by-step explanation:

The corresponding sides of similar triangles are in the same ratio to each other.

      3/5 = (3 + x)/20     Multiply each side by 20

20×3/5 = 3 + x

       12 = 3 + x             Subtract 3 from each side

        x = 9

=====

      4/5 = (4 + y)/20     Multiply each side by 20

20×4/5 = 4 + y

       16 = 4 + y              Subtract 4 from each side

        y = 12

=====

      3/5 = (3 + x + u)/60     Multiply each side by 60

60×3/5 = 3 + x + u

       36 = 3 + x + u             Insert the value of x

       36 = 3 + 9 + u

       36 = 12 + u                 Subtract 12 from each side

         u = 24

=====

      4/5 = (4 + y + v)/60     Multiply each side by 60

60×4/5 = 4 + y + v

       48 = 4 + y + v             Insert the value of y

       48 = 4 + 12 + v

       48 = 16 + v                 Subtract 16 from each side

         v = 32

x = 9; y = 12; u = 24; v = 32

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