Here is how you solve...
Q= 3a+5ac
take out the common variable.
Q= a(3+5c)
get A by its self so divide each side by (3+5c).
Q/a(3+5c)= a(3+5c)/(3+5c)
Q/a(3+5c)=A
So your answer is A= Q/a(3+5c)
hope that helped.
Answer:
Variance = 1,227.27
Standard deviation = 35.03
Step-by-step explanation:
To calculate these, we use the following formulas:
Mean = (sum of the values) / n
Variance = ((Σ(x - mean)^2) / (n - 1)
Standard deviation = Variance^0.5
Where;
n = number of values = 20
x = each value
Therefore, we have:
Sum of the values = 29 + 32 + 36 + 40 + 58 + 67 + 68 + 69 + 76 + 86 + 87 + 95 + 96 + 96 + 99 + 106 + 112 + 127 + 145 + 150 = 1,674
Mean = 1,674 / 20 = 83.70
Variance = ((29-83.70)^2 + (32-83.70)^2 + (36-83.70)^2 + (40-83.70)^2 + (58-83.70)^2 + (67-83.70)^2 + (68-83.70)^2 + (69-83.70)^2 + (76-83.70)^2 + (86-83.70)^2 + (87-83.70)^2 + (95-83.70)^2 + (96-83.70)^2 + (96-83.70)^2 + (99-83.70)^2 + (106-83.70)^2 + (112-83.70)^2 + (127-83.70)^2 + (145-83.70)^2 + (150-83.70)^2) / (20 - 1) = 23,318.20 / 19 = 1,227.27
Standard deviation = 1,227.27^0.5 = 35.03
First it was 186,000 and then the second year it was 202,000 what is the expenses is 16000
Answer:
The least number of steps she takes to reach 20 m is 118 steps
Step-by-step explanation:
For Laura, the length of a walking step = 50 cm = 0.5 m
The repeating number of steps she takes = Two steps forward one step backwards
The number of forward steps it would take for her to reach 20 m = (20 m)/(0.5 m) = 40 steps
Given that she always takes two steps forward and one step backwards, we have;
The number of steps forward every three steps = 2 step forward + (-1) step (backward)
The number of steps forward every three steps = 2 - 1 = 1 step forward
To reach 39 steps forward, she would need 39 × 3 = 117 steps
To get to the 40 steps she needs just a step forward, making the total number of steps to reach 40 steps = 117 + 1 = 118 steps
Therefore, the least number of steps she takes to reach 20 m = 118 steps.
