Answer:
1st problem: b) 
2nd problem: c) 
Step-by-step explanation:
1st problem:
The formula/equation you want to use is:
where
t=number of years
A=amount he will owe in t years
P=principal (initial amount)
r=rate
n=number of times the interest is compounded per year t.
We are given:
P=2500
r=12%=.12
n=12 (since there are 12 months in a year and the interest is being compounded per month)
Time to clean up the inside of the ( ).
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2nd Problem:
Compounded continuously problems use base as e.
P is still the principal
r is still the rate
t is still the number of years
A is still the amount.
You are given:
P=2500
r=12%=.12
Let's plug that information in:
.
Answer:
Quantity of soap left after Juan washes 8 regular loads and 5 heavy loads of laundry 
pounds.
Step-by-step explanation:
Number of scoop of soap used to wash a regular load of laundry = One 0.15 pound scoop
Number of scoops of soap used to wash heavy work clothes = Two 0.15 pound scoops
As Juan washes 8 regular loads and 5 heavy loads of laundry,
Total quantity of soap used = 
pounds
As a box of laundry soap weighed 15.6 pounds,
quantity of soap left after Juan washes 8 regular loads and 5 heavy loads of laundry 
pounds.
The answer should be 3.5 pounds. You divide 56 by 16 to get your answer
Answer:
$1.75 because if u add $3.50 + $1.75 u get $5.25 subtract that from $7.00 u get $1.75
Sum means to Add.
So the sum of d and 9 would be d + 9
