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rewona [7]
2 years ago
14

Write the equation of a line in slope-intercept form with the given slope that passes through the given point:

Mathematics
1 answer:
dimaraw [331]2 years ago
7 0
Y=3x+12 (its the first option)
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4x(x + 3) +7x = what is the answer please
wel
4x^2+12x+7x
4x^2+19x

Was it meant to equal something or are you just simplifying the equation?
5 0
3 years ago
Read 2 more answers
Please help will mark brainliest
Levart [38]

Answer:

14

Step-by-step explanation:

7 0
3 years ago
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Write an equation that you can use to find the m
Ostrovityanka [42]
M =180 - 148-24 I THINK this shoud work
5 0
3 years ago
The surface area of the prism below is 264 square units . Find the missing dimensions of this prism. ( picture is in the picture
nignag [31]

Answer:

The missing dimension is 4 units.

Step-by-step explanation:

In the given prism,

Of all the surfaces,

There are three rectangular surfaces and two triangular surfaces

<h2>Analyzing areas of rectangular surfaces:</h2>

1)The two rectangles with dimensions of 15 units and 5 units:

The area of each rectangle = Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 5 units.

Area of each rectangle = 15\times 5 ;

Area of each rectangle = 75 square units.

Sum of areas of the two rectangles = 2\times 75

Sum of areas of the two rectangles = 150 square units (equation 1)

2) The rectangle with the dimensions 15 units and 6 units:

The area of thus rectangle=  Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 6 units.

Area of the rectangle = 15\times 6 ;

Area of the rectangle = 90 square units. (equation 2)

From equation 1 and equation 2,

Therefore sum of areas of all rectangles in the prism = 150 + 90

Sum of areas of rectangles = 240 square units.

We also know,

Total surface area of the prism = Sum of areas of triangles + Sum areas of rectangles

Given, Total surface area of prism = 264 square units.

Therefore from the formula,

Sum of areas of triangles = Total surface area - sum of areas of reactangles

Sum of areas of triangles = 264 - 240

Sum of areas of triangles = 24 square units. (equation 3)

Let the missing dimension be 'h units'

<h2>Calculating sum of areas of triangles:</h2>

From diagram,both triangles are congruent,hence have the same area

Area of a triangle = \frac{1}{2}\times base\times height

From diagram,

Base = 6 units,

Height = h units.

Area of a triangle =\frac{1}{2}\times 6\times h = 3h square units.

Sum of the areas of both triangles = 3h+3h = 6h square units.

Using equation 3, we get

6h = 24;

h = \frac{24}{6}

Therefore,

h = 4 units.

Therefore,

The missing dimension is 4 units.

4 0
3 years ago
-4x-2y=-10<br> 3x+y=4<br> Using substitution
Citrus2011 [14]

Let get x from the first equation

-4x=+2y-10

x=-1/2y + 5/2

Now substitute the x in the second equation

3(-1/2y+5/2)+y=4

-3/2y + 15/2 + y =4

Move the terms without the y to the other side

-3/2y + y = -15/2 +4

Now multiple both side by 2

-3y +2y = -15+8

-y = -7

Y = 7 (ANSWER)

Now we substitute the y in the first equation so we can get the x

x = -1/2 (7) + 5/2

x = -7/2 + 5/2

x = -2/2

X = -1 (SECOND ANSWER)

3 0
3 years ago
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