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Ne4ueva [31]
3 years ago
15

Solve x + 5x – 14 = 0

Mathematics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer: x = 7/3

Step-by-step explanation:

You join the X’s first which will give you

6x-14 = 0

Then you move the 14 to the right

6x = 14

Then you dived them and it give you 7/3

Hope this helped

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What is the main advantage banking services offer?
Maru [420]
I think it's a profit or a lone.
3 0
4 years ago
3. If log 2 =a and log 3=b, the expression 9/32<br> is equivalent to
klemol [59]

Answer:

\frac{9}{32}  =  \frac{{10}^{2b} }{{10}^{5a}}

Step-by-step explanation:

It is given that:

log 2=a and log 3=b

This implies that:

2 =  {10}^{a}

and

3 =  {10}^{b}

Now we know that:

\frac{9}{32}  =  \frac{ {3}^{2} }{ {2}^{5} }

We substitute to get:

\frac{9}{32}  =  \frac{ ({10}^{b}) ^{2} }{( {10}^{a})^{5} }

We simplify to get:

\frac{9}{32}  =  \frac{{10}^{2b} }{{10}^{5a}}

5 0
3 years ago
Parallelogram JKLM is shown on the coordinate plane below:
Harlamova29_29 [7]

if JKLM is rotated 270° clockwise around the origin, the new vertices is at:

J'(-2, -6), K'(-6, -4), L'(-3, -3) and M'(1, -5)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

Rotation is the movement of a figure about a fixed point. If a point A(x, y) is rotated 270° clockwise around the origin, the new point is A'(-y, x).

The vertices of the parallelogram is at J(-6, 2), K(-4, 6), L(-3, 3) and M(-5, -1). Therefore if JKLM is rotated 270° clockwise around the origin, the new vertices is at:

J'(-2, -6), K'(-6, -4), L'(-3, -3) and M'(1, -5)

Therefore K′(−6, −4); L′(−3, −3) is the correct option

Find out more at: brainly.com/question/11707700

8 0
3 years ago
A horse can run 44 per second for several minutes. A cheetah can run faster (88 feet per second) but can only sustain its top sp
qaws [65]

Answer:

44 feet

If it takes the horse 44 feet per second, and it takes the cheetah 88 feet, the difference is 44.

So, the horse must be 44 feet ahead to be safe. Hope it helps!

6 0
3 years ago
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
frozen [14]

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

(x,y)\to (y,-x)

Using this rule, we get

A(-3,6)\to A'(6,3)

B(2,9)\to B'(9,-2)

C(1,1)\to C'(1,-1)

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

7 0
4 years ago
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