Answer:
BAC=15
Step-by-step explanation:
angle BOA= 180-30= 150
triangle BAO is
isosceles because it has two equal sides, radii of a circumference so the angles ABO=BAO=(180-150)/2=15
Answer:
55 days
Step-by-step explanation:
Given
Jim ran 15 miles in 5 days
no. of miles ran in 5 days = 15 miles
dividing LHS and RHS by 5
no. of miles ran in 5/5(=1) days = 15/5 miles = 3 miles
no. of miles ran in 1 day = 3 miles
let the no. of days taken to run 165 miles be x ----A
No of miles ran in x days = x*no. of miles ran in 1 day = 3x miles
thus, From A
3x = 165
x = 165/3 = 55
Thus, it took 55 days for JIM to run 165 miles
B is the answer show that segments WX AND YZ have equal lengths
Answer:
6+3x=w
Step-by-step explanation:
6 *more* more always means +
and then three *times* times always means *
so it would equal 6+3x=w
Answer:
1)-
How to solve your question
Your question is
4(4−72)−9(5+2)
4(4y-7y^{2})-9(5y+2)4(4y−7y2)−9(5y+2)
Simplify
1
Rearrange terms
4(4−72)−9(5+2)
4({\color{#c92786}{4y-7y^{2}}})-9(5y+2)4(4y−7y2)−9(5y+2)
4(−72+4)−9(5+2)
4({\color{#c92786}{-7y^{2}+4y}})-9(5y+2)4(−7y2+4y)−9(5y+2)
2
Distribute
4(−72+4)−9(5+2)
{\color{#c92786}{4(-7y^{2}+4y)}}-9(5y+2)4(−7y2+4y)−9(5y+2)
−282+16−9(5+2)
{\color{#c92786}{-28y^{2}+16y}}-9(5y+2)−28y2+16y−9(5y+2)
3
Distribute
−282+16−9(5+2)
-28y^{2}+16y{\color{#c92786}{-9(5y+2)}}−28y2+16y−9(5y+2)
−282+16−45−18
-28y^{2}+16y{\color{#c92786}{-45y-18}}−28y2+16y−45y−18
4
Combine like terms
2)
−17y+17z+24
See steps
Step by Step Solution:

STEP1:Equation at the end of step 1
((24 - 4 • (5y - 6z)) + 3y) - 7z
STEP2:
Final result :
-17y + 17z + 24
−282+16−45−18
-28y^{2}+{\color{#c92786}{16y}}{\color{#c92786}{-45y}}-18−28y2+16y−45y−18
−282−29−18
-28y^{2}{\color{#c92786}{-29y}}-18−28y2−29y−18
Solution
−282−29−18