Answer:
At 10 days
Step-by-step explanation:
180 - 8x = 160 - 6x
Solve X (which equals to 10 days)
(x = amount of days)
Parallel are two equations that have the same slope but different y intercepts.
If the y intercepts are also the same, it is just the same line.
Compute the average number of units consumed: 504, 519, 576, 321, 256, 101, 76, 75, 127, 289, 367, and 511.
Komok [63]
The answer is about 310.17. Just have to add them all together and than divide by 12.
I think it’s 25%
Because 70 divided by 10 is 7
Which is then 10% so 20% is 14 then 5% is half of 7 which is 3.5
So 70 -7-7-3.5=52.5 which is 25%
9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
