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Dima020 [189]
4 years ago
7

2,783 the value of 2 is time

Mathematics
1 answer:
Hoochie [10]4 years ago
5 0
The value of 2 is two thousand
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the answer is { } "an empty set or phi"

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Intercontinental, Inc., uses a perpetual inventory system. Consider the following information about its inventory: July 1, purch
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Answer:

Using weighted average, the cost of goods sold for the sale of 23 units on July 31 is $2,504.70, and the inventory balance at July 31 is $ 1,306.90.

Step-by-step explanation:

Since Intercontinental, Inc., uses a perpetual inventory system, and on July 1, purchased 10 units for $ 910 or $ 91 per unit; on July 3, purchased 15 units for $ 1,590 or $ 106 per unit; on July 14, it sold 20 units; on July 17, purchased 20 units for $ 2,300 or $ 115 per unit; on July 28, purchased 10 units for $ 1,190 or $ 119 per unit; and on July 31, sold 23 units, to determine the average costs and the inventory balance as of July 31, the following calculations must be performed:

(910 +1590 + 2300 + 1190) / (10 + 15 + 20 + 10) = X

5990/55 = X

108.90 = X

108.90 x 23 = 2504.7

(55 x 108.9) - (43 x 108.9) = X

5990 - 4683.10 = X

1306.90 = X

Using weighted average, the cost of goods sold for the sale of 23 units on July 31 is $ 2504.70, and the inventory balance at July 31 is $ 1,306.90.

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The perimeter of the rectangle is 56 cm. Find the value of x.<br> 10 cm<br> 3x cm
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\bf cos(2\theta)=\cfrac{5}{6}\implies 2cos^2(\theta)-1=\cfrac{5}{6}\implies 2cos^2(\theta)=\cfrac{5}{6}+1&#10;\\\\\\&#10;2cos^2(\theta)=\cfrac{11}{6}\implies cos^2(\theta)=\cfrac{11}{12}\implies cos(\theta)=\pm\sqrt{\cfrac{11}{12}}


now, bear in mind, the square root gives us +/- versions, so, which is it? well, we know the angle is in the range of "<span>0 ≤ θ < π/2", that simply means the 1st quadrant, so, we'll use the positive one then

</span>\bf cos(\theta)=\cfrac{\sqrt{11}}{\sqrt{12}}\implies cos(\theta)=\cfrac{\sqrt{11}}{2\sqrt{3}}&#10;\\\\\\&#10;\textit{now, let's rationalize the denominator}&#10;\\\\\\&#10;\cfrac{\sqrt{11}}{2\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{\sqrt{11}\cdot \sqrt{3}}{2\sqrt{3^2}}\implies \cfrac{\sqrt{11\cdot 33}}{2\cdot 3}\implies \boxed{\cfrac{\sqrt{33}}{6}}<span>
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4 years ago
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