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Dima020 [189]
3 years ago
7

2,783 the value of 2 is time

Mathematics
1 answer:
Hoochie [10]3 years ago
5 0
The value of 2 is two thousand
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What are the x-intercept and y-intercept of the graph of y=13x−6 ?
mestny [16]

Answer:

x intercept is 6/13

y intercept is -6

Step-by-step explanation:

x intercepted when y is zero.

y intecepted when x is zero...

3 0
3 years ago
Either use technology to find the P-value or use
Akimi4 [234]

Answer:

The first step is calculate the degrees of freedom, on this case:  

df=n-1=21-1=20  

Since is a one side left tailed test the p value would be:  

p_v =P(t_{(20)}  

And we can use the following excel code to find it: "=T.DIST(-0.024,20,TRUE)"

Step-by-step explanation:

Data given and notation  

\bar X represent the mean

s represent the sample standard deviation

n=21 sample size  

\mu_o =140 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t=-0.024 would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean for the widths of tornadoes is lower than 140 yd, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

The statistic is given by: t = -0.024

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=21-1=20  

Since is a one side left tailed test the p value would be:  

p_v =P(t_{(20)}  

And we can use the following excel code to find it: "=T.DIST(-0.024,20,TRUE)"

Based on the p value obtained we can conclude that we FAIL to reject the null hypothesis at any significance level selected \alpah=0.01,0.05,0.1

7 0
3 years ago
A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med
Troyanec [42]
The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test -  No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is  \frac{0.0396}{0.0396+0.0096}= \frac{33}{41}

The probability of someone picked at random has cancer given that test result indicates no cancer is \frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}

7 0
3 years ago
What Did the Baby Porcupine Say When It Backed into a Cactus??
Katen [24]

Answer:

Is that you, Mommy?

Step-by-step explanation:

:)

8 0
3 years ago
Read 2 more answers
HELP PLEASEEE WITH EXPLANATION PLEASEEE
Volgvan
Ziad is 30 and marc is 10
4 0
3 years ago
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