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2 years ago

find the length of the side of square with an area of 121 in2. A.484 in, B.30.25 in, C.11 in, D.6.5 in

Mathematics

2 answers:

kati45 [8]2 years ago

8 0

The correct answer would have to be c

marishachu [46]2 years ago

3 0

For a square, the area is the square of the side length (length x width = area, but in a square length = width). That means the side length is the square root of the area.

In this case the side length is the square root of 121, which is 11. Answer is C.

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Find a measurement in centimeters of an object. Look through books, magazines, or the Internet. Then write the measurement as pa

ser-zykov [4K]

A book 2meters I found it so yea I concert and did a

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2 years ago

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Timothy stated that the sum of 0.9 + (-9/10) was 18/20.

Evgesh-ka [11]

Answer:

18/10

Step-by-step explanation:

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2 years ago

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Use the linear combination method to solve the system of equations. Explain each step of your solution. 2x-3y=13 4x-y=-9

Tems11 [23]

2x -3y = 13

4x -y = -9

Multiply the second equation by -3 to make the coefficient of Y opposite the first equation.

4x -y = -9 x -3 = -12x + 3y = 27

Now add this to the first equation:

2x -12x = -10x

-3y +3y = 0

13 +27 = 40

Now you have :

-10x = 40

Divide each side by -10:

x = 40 / -10

x = -4

Now you have a value for x, replace that into the first equation and solve for y:

2(-4) - 3y = 13

-8 - 3y = 13

Add 8 to both sides:

-3y = 21

Divide both sides by -3:

y = 21/-3

y = -7

Now you have X = -4 and y = -7

(-4,-7)

3 0

2 years ago

a polygon has an area of 225 square meters. A similar polygon is created with an area that is triple the first. By what factor i

GuDViN [60]

The area of the original polygon is:
A = 225 m ^ 2
The similar polygon area is:
A '= (k ^ 2) * (A)
Substituting values:
3 * 225 = (k ^ 2) * (225)
Clearing k we have:
k ^ 2 = 3
k = (3) ^ (1/3)
Answer:
The length of each side increased by:
k = (3) ^ (1/3)

6 0

2 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x + 2}$ with x = 0: $y = \sqrt [3] {2}$ in the same way is defined.

Answer:

$y = \sqrt {x-2}$

Option b

6 0

3 years ago