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nevsk [136]
3 years ago
13

find the length of the side of square with an area of 121 in2. A.484 in, B.30.25 in, C.11 in, D.6.5 in

Mathematics
2 answers:
kati45 [8]3 years ago
8 0
The correct answer would have to be c
marishachu [46]3 years ago
3 0
For a square, the area is the square of the side length (length x width = area, but in a square length = width). That means the side length is the square root of the area.

In this case the side length is the square root of 121, which is 11. Answer is C.
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Dmitriy789 [7]

Answer/Step-by-step explanation:

2x-5y=9

Add 5y  to both sides of the equation.

2x=9+5y

Divide each term by 2 and simplify.

Divide each term in 2x=9+5y by 2

\frac{2x}{2} =\frac{9}{2} +\frac{5y}{2}

Cancel the common factor of 2.

Divide x by 1.

x=\frac{9}{2} +\frac{5y}{2}

y=\frac{-9}{5} +\frac{2x}{5}

----------------------------------------------------------------------------------------------------------------

3x+4y=2

Add 4y to both sides of the equation

3x=2+4y

Divide each term by 3 and simplify.

Divide each term in 3x=2+4y by 3.

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Cancel the common factor of 3.

Divide x by 1.

x=\frac{2}{3} +\frac{4y}{3}

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3 years ago
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Jet001 [13]

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5 0
3 years ago
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Deffense [45]

9514 1404 393

Answer:

  4. height: 5√3 cm; area: 25√3 cm²

  5. 30√2 ft ≈ 42.43 ft

Step-by-step explanation:

4. The height of an equilateral triangle is (√3)/2 times the side length, so is ...

  height = (√3)/2 × (10 cm) = 5√3 cm

The area is given by the formula ...

  A = 1/2bh

  A = 1/2(10 cm)(5√3 cm) = 25√3 cm²

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5. The diagonal of a square is √2 times the side length, so the distance from 3rd to 1st base is ...

  (30 ft)√2 ≈ 42.43 ft

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The length of the diagonal of a square is something you should be familiar with. If you're not, you can figure the distance using the Pythagorean theorem.

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6 0
3 years ago
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Vadim26 [7]

Answer:

Light to chemical

Step-by-step explanation:

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3 0
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