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2 years ago

Can someone plzz help me with these 2 questions. thanks!

Mathematics

1 answer:

Deffense [45]2 years ago

6 0

9514 1404 393

Answer:

4. height: 5√3 cm; area: 25√3 cm²

5. 30√2 ft ≈ 42.43 ft

Step-by-step explanation:

4. The height of an equilateral triangle is (√3)/2 times the side length, so is ...

height = (√3)/2 × (10 cm) = 5√3 cm

The area is given by the formula ...

A = 1/2bh

A = 1/2(10 cm)(5√3 cm) = 25√3 cm²

5. The diagonal of a square is √2 times the side length, so the distance from 3rd to 1st base is ...

(30 ft)√2 ≈ 42.43 ft

The length of the diagonal of a square is something you should be familiar with. If you're not, you can figure the distance using the Pythagorean theorem.

d = √(30² +30²) = √1800 ≈ 42.43 . . . feet

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If y = 124 and x = 12, find y when x = -24.

tatyana61 [14]

Answer:

y = -248

Step-by-step explanation:

Hi there!

Set up a proportion:

$\displaystyle\frac{124}{12} =\frac{y}{-24}$

Cross-multiply:

$12y=(-24)(124)\\12y=-2976\\y=-248$

I hope this helps!

7 0

2 years ago

the price of a taxi ride in phoenix includes an initial fee of $2.75 plus $2.20 per mile. write an equation to show the total pr

ki77a [65]

The format is y = mx + b
where y would be your C
x would be your M
m would be the price per mile (2.20)
and b would be your initial fee (2.75)

put this together in that format and we get
C = 2.20M + 2.75

4 0

3 years ago

Find the area of the circle. 12 ft

Ratling [72]

Answer:

Area of the circle is 113.04 ft²

Step-by-step explanation:

Given:

Diameter of circle = 12 feet

To Find:

Area of the circle

Using formula:

$\\ \: \: \dashrightarrow \: \: \:{\underline{\boxed{ \bf{Area_{( circle)} = \pi r^2}}}} \\ \\$

Where,

π = 3.14
Diameter = 12 feet
Radius = 12/2 = 6 feet

On substituting the required values, we get:

$\\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 3.14 \times {(6)}^{2} \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 3.14 \times 36 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 113.04 \: {ft}^{2} \\ \\ \\$