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3 years ago

Show how to solve the problem 378 times 6 using place value with regrouping. Explain how you knew when to regroup

Mathematics

2 answers:

JulijaS [17]3 years ago

7 0

Answer:

2268

Step-by-step explanation:

We have to solve the problem 378 dimes 6 using place value.

Place of 8 in 378 = once

Place of 7 in 378 = Tens

Place of 3 in 378 = Hundred

Now we can write this number as ( 300 + 70 + 8 )

( 300 + 70 + 8 ) × 6 = (300) × 6 + 70 × 6 + 8 × 6

= 1800 + 420 + 48

= 2268

kkurt [141]3 years ago

4 0

378 x 6 as (300 x 6) + (70 x 6) + (8 x 6) = 1800 + 420 + 48 = 2268

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Solve the system using elimination: -3x - 3y = 12 -9x + 3y = -24 The answer is not (-1,-3)

FinnZ [79.3K]

Answer:

{x = 1, y = -5

Step-by-step explanation:

Solve the following system:

{-3 x - 3 y = 12 | (equation 1)

{3 y - 9 x = -24 | (equation 2)

Swap equation 1 with equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

{-(3 x) - 3 y = 12 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

0 x - 4 y = 20 | (equation 2)

Divide equation 1 by 3:

{-(3 x) + y = -8 | (equation 1)

{0 x - 4 y = 20 | (equation 2)

Divide equation 2 by 4:

{-(3 x) + y = -8 | (equation 1)

{0 x - y = 5 | (equation 2)

Multiply equation 2 by -1:

{-(3 x) + y = -8 | (equation 1)

{0 x+y = -5 | (equation 2)

Subtract equation 2 from equation 1:

{-(3 x)+0 y = -3 | (equation 1)

{0 x+y = -5 | (equation 2)

Divide equation 1 by -3:

{x+0 y = 1 | (equation 1)

{0 x+y = -5 | (equation 2)

Collect results:

Answer: {x = 1 , y = -5

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3 years ago

Hello, this is the owner sister, but can you please help me?b Please dont remove this for silly things

kondaur [170]

The answer is 825

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3 years ago

Solve the following formula for the indicated variable. – 5x – 3y = 13: solve for y.

SashulF [63]

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Answer:

y = -5/3x -13/3

Step-by-step explanation:

In any "solve for ..." problem, it is useful to start by identifying where the target is and what has been done to it. Here, y is in one term on the left side of the equation and it has had these things done to it:

multiply by -3
add -5x

We want to undo these in reverse order. We undo addition by adding the opposite. We undo multiplication by multiplying by the reciprocal (equivalently, dividing). Whatever we do to one side of the equation, we must also do to the other side.

So, first we add the opposite of -5x to both sides of the equation.

-5x +5x -3y = 13 +5x

-3y = 13 +5x . . . . . . . . . collect terms

Next, we undo the multiplication by -3. We can do that by multiplying both sides by 1/(-3) = -1/3.

(-1/3)(-3y) = (-1/3)(13 +5x)

y = -5/3x -13/3 . . . . . also we rearranged the terms to standard form

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valkas [14]

Answer:

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Step-by-step explanation:

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Answer:

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