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3 years ago

Show how to solve the problem 378 times 6 using place value with regrouping. Explain how you knew when to regroup

Mathematics

2 answers:

JulijaS [17]3 years ago

7 0

Answer:

2268

Step-by-step explanation:

We have to solve the problem 378 dimes 6 using place value.

Place of 8 in 378 = once

Place of 7 in 378 = Tens

Place of 3 in 378 = Hundred

Now we can write this number as ( 300 + 70 + 8 )

( 300 + 70 + 8 ) × 6 = (300) × 6 + 70 × 6 + 8 × 6

= 1800 + 420 + 48

= 2268

kkurt [141]3 years ago

4 0

378 x 6 as (300 x 6) + (70 x 6) + (8 x 6) = 1800 + 420 + 48 = 2268

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Answer: " m∠ACD = 40° " .
______________________________________________________
Explanation:
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We are asked to find: "m∠ACD" ;
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Note: m∠ACD = m∠ABD ;
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So, given:

m∠ACD = (4x + 4)° ;

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4x + 4 = 6x - 14 ;

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Add "14" to each side of the equation; and subtract "4x" from each side of the equation ;

4x + 4 + 14 - 4x = 6x - 14 + 14 - 4x ;

to get:

18 = 2x ;

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2x / 2 = 18/2 ;

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Now, to solve for: " m∠ACD " :
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Substitute "9" for "x" ;

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Answer: " m∠ACD = 40° " .
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Let us check our answer:
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m∠ACD = 40 ; and m∠ABD = (6x - 14) ;

m∠ACD = ∠ABD ;

Since m∠ABD = (6x - 14) ;

If x = 9; if we plug in "9" into the expression for "m∠ABD" ; will the value obtained be "40" ??

m∠ABD = (6x - 14) ; Let us plug in "9" for "x" ; to see if the value obtained is "40"

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6x - 14 = ? 40 ?? Yes!
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