Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z =
~ N(0,1)
where,
= population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P(
<
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
Answer:
200
Step-by-step explanation:
bruh truss me❤️
First you have to find the area of the WHOLE BOX. So you multiply,
8×7=56
Then find the area of the small box,
5×4=20
It says take away the area of the small box from the whole box and you should do just that: 56-20=36
The area of the shaded region is 36cm²
Answer:
0.75x
Step-by-step explanation:
Given that :
Discount rate= 25%
Original price = x
Discounted price of jacket :
(100 - discount rate)% * original price
(100 - 25)% * x
75% * x
0.75x
Answer:
6
Step-by-step explanation:
14/2-3+6/3=7-3+2=4+2=6