Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
Answer:
x = 2.66666667
Step-by-step explanation:
3(x + 1) = 11
We multiply both x and 1 by 3 and get
3x + 3 = 11
Now we subtract 3 from both sides
3x + 3 - 3 = 11 - 3
3x = 8
Now divide both sides by 3
3x/3 = 8/3
x = 2.66666667
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Answer:
72°
Step-by-step explanation:
Given that the radius(r) of the circle is 10 units and the length of arc ABC is 16π
The length of arc ABC = 
Where θ is the central angle in degrees.
Since the length of arc ABC is 16π,

The angle in a circle = 360°, therefore:
Central angle for arc AB (θ) = 360 - Central angle for arc ABC = 360 - 288 = 72°
Therefore the arc measure of arc AB is 72°
So the tree is 40 ft and then the shadow is 30 so then do 40 -30 = 10 ft difference so then for the second tree do 20 + 10 = 30 ft because the 10 ft difference so the answer is 30 ft tall
Answer:
118°
Step-by-step explanation:
the angle measures of a triangle will always add up to 180
so..
42+20=62
180-62=118