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iogann1982 [59]
3 years ago
15

Partial products of 56×31

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0
You start by putting the numbers up and down like this
56
x 31
--1------
1 56
1580
---------
1736
On top of the 5 at the bottom you put 2 ones on top because 5+8 is 13 hope this helps
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What is the remainder of (2^91 x 6^27) divided by 7?
kondaur [170]
2\equiv2\mod7
2^2\equiv4\mod7
2^3\equiv8\equiv1\mod7

91=3(30)+1
\implies2^{91}\equiv(2^3)^{30}\times2^1\equiv1^{30}\times2\equiv2\mod7

6\equiv-1\mod7
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\implies2^{91}\times6^{27}\equiv2\times6\equiv12\equiv5\mod7
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Gnesinka [82]
<h2><u>Answer</u>:-</h2>

<h3>Given:-</h3>

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Answer:

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Step-by-step explanation:

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