The answer to that is 81 :)
Answer:
- future value: $4873.61
- interest: $873.61
Step-by-step explanation:
Your table appears to be incomplete and not capable of answering this question. So, we'll use the future value formula:
FV = P(1 +r/n)^(nt)
for principal P, interest rate r, n compoundings per year for t years.
Here, we have P=$4000, r=0.05, n = 2, t = 4, so the future value is ...
FV = $4000(1.025^8) ≈ $4,873.61
__
This amount includes the original $4000 plus interest, so the interest is ...
$4,873.61 -4,000 = $873.61
<h3>
Answer: 6a^3-6a^2b+3ab-3b^2</h3>
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Work Shown:
(2a^2+b)(3a-3b)
c(3a-3b) ..... let c = 2a^2+b
3ac-3bc .... distribute
3a(c)-3b(c)
3a(2a^2+b)-3b(2a^2+b) .... plug in c = 2a^2+b
3a(2a^2)+3a(b)-3b(2a^2)-3b(b) ... distribute
6a^3+3ab-6a^2b-3b^2
6a^3-6a^2b+3ab-3b^2
You could also use the FOIL rule to get the same result. The box method is a visual way to keep track of the terms.
Answer:
a=-2
So yep. ;)
Step-by-step explanation:
Alright, so, (2,12), 2 is the x and 12 is the y.
Stick them into the equation: 
Then, solve:
a = -2
So yes, they're on the graph.
Hope this helped! :)
