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4 years ago

5

4x - y Please someone help me I don't understand?

1 answer:

Alja [10]4 years ago

8 0

Divide each term by <span>4</span> and simplify.Tap for less steps...Divide each term in <span><span><span>4x</span>=y</span><span><span>4⁢x</span>=y</span></span> by <span>44</span>.<span><span><span><span>4x</span>4</span>=<span>y4</span></span><span><span><span>4⁢x</span>4</span>=<span>y4</span></span></span>Reduce the expression by cancelling the common factors.So your answer would be x=y over 4

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NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+121t

Alenkasestr [34]

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

$h(t)=-4.9t^2+121t+283$

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

$h(t)=0\implies-4.9t^2+121t+283=0$

Using the quadratic formula, the solution for our problem is

$\begin{gathered} t=\frac{-(121)\pm\sqrt{(121)^2-4(-4.9)(283)}}{2(-4.9)} \\ =\frac{121\pm142.083778...}{9.8} \\ =\frac{121+142.083778...}{9.8} \\ =26.8452834694... \end{gathered}$

The rocket splashes after 26.845 seconds.

The maximum of this function happens at the root of the derivative. Differentiating our function, we have

$h^{\prime}(t)=-9.8t+121$

The root is

$-9.8t+121=0\implies t=\frac{121}{9.8}=12.347$

Then, the maximum height is

$h(12.347)=1029.99$

1029.99 meters above sea level.

6 0

1 year ago

Let f(x) = (x − 3)−2. Find all values of c in (1, 7) such that f(7) − f(1) = f '(c)(7 − 1). (Enter your answers as a comma-separ

Sidana [21]

Answer:

This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3

Step-by-step explanation:

The given function is

$f(x)=(x-3)^{-2}$

When we differentiate this function with respect to x, we get;

$f'(x)=-\frac{2}{(x-3)^3}$

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)

This implies that;

$0.06-0.25=-\frac{2}{(c-3)^3} (6)$

$-0.19=-\frac{12}{(c-3)^3}$

$(c-3)^3=\frac{-12}{-0.19}$

$(c-3)^3=63.15789$

$c-3=\sqrt[3]{63.15789}$

$c=3+\sqrt[3]{63.15789}$

$c=6.98$

If this function satisfies the Mean Value Theorem, then f must be continuous on [1,7] and differentiable on (1,7).

But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.

3 0

3 years ago

Please help I'm not vary good at math.

baherus [9]

I hope you find it helpful

3 0

3 years ago

Which times and distances are represented by the function?

alexdok [17]

Can u put a picture of the question with this so I can answer it.

7 0

3 years ago

In the last draw, the grand prize was won. If there are three winners, each would have received $ 720,000; if there are four win

larisa86 [58]

Answer:

b) 15 winners

Step-by-step explanation

if 3 winners get $720,000 each that means there is $2,160,000 total. So if each winner gets $144,000 each that means there are 15 winners.

(2,160,000/ 144,000)

5 0

3 years ago