Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
108=2x-4(2x-9)
108=2x-8x+36
108=-6x+36
-36 -36
72=-6x
72/-6=-6x/-6
-12=x
I believe it's 3 months because 12 divided by 4 is 3.
a. (f+g)(x) = 8x+2
b. (f-g)(x) = 4x-6
Step-by-step explanation:
Given
<u>a. (f+g)(x)</u>
<u>b. (f-g)(x)</u>
Hence,
a. (f+g)(x) = 8x+2
b. (f-g)(x) = 4x-6
Keywords: Functions
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Answer:
C.
Step-by-step explanation:
The pythagorean theorem shows a^2+b^2=c^2.
a=8, b=15, c= the unknown distance
8^2+15^2=c^2