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Vladimir79 [104]
3 years ago
6

A rectangular pan has a length that is the width. The total area of the pan is 432 in.2. What is the width of the cake pan? A =

lw 10.4 in. 13.9 in. 18 in. 24 in.
Mathematics
1 answer:
spayn [35]3 years ago
4 0

Answer:

Let width = w

length = 4w/3

Area = 432 = length*width = w*4w/3

4w^2/3 = 432

w^2 = 432*3/4 = 324

w = 18

so the width of the cake pan is 18 inches.

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Find the value of x in each case: Given: Iso. ΔABC, HM ∥DG Find: x, m∠CAB, m∠CBA
AleksAgata [21]

1. Start with ΔCIJ.

  • ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
  • the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
  • ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.

2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So

m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.

3. Consider ΔCKL.

  • ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
  • ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
  • the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
  • ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.

4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So

m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.

5. ΔABC is isosceles, then angles adjacent to the base are congruent:

m∠KBA=m∠JAB → 222°-8x=205°-7x,

7x-8x=205°-222°,

-x=-17°,

x=17°.

Then m∠CAB=m∠CBA=205°-7x=86°.

Answer: 86°.

3 0
3 years ago
Read 2 more answers
Solve the simultaneous equation 2x+5y=6 and 5x-2y=9​
Ilia_Sergeevich [38]

Answer:

x = \frac{57}{29} \ , \ y = \frac{12}{29}

Step-by-step explanation:

                            2x + 5y = 6     --------( 1 )

                            5x - 2y = 9     --------( 2 )

                        _____________

     ( 1 ) x 5 =>     10x + 25y = 30   -----------( 3 )

     ( 2 ) x 2 =>    10x - 4y = 18       ----------- ( 4 )

                       ______________

    ( 3 ) - ( 4 ) =>    0 +  29y = 12

                                   y = \frac{12}{29}

Substitute y in ( 1 ) =>

                            2x + (5 \times \frac{12}{29}) = 6\\\\2x + \frac{60}{29} = 6\\\\2x = 6 - \frac{60}{29}\\\\2x = \frac{174 - 60}{29}\\\\x = \frac{114}{29 \times 2}\\\\x = \frac{57}{29}

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3 years ago
A local chess club claims that the length of time to play a game has a standard deviation of more than 13 minutes. Write sentenc
tatyana61 [14]

Answer:

Step-by-step explanation:

A type I error occurs when the researcher rejects the null hypothesis when it is actually true.

A type II error occurs when the research fails to reject the null hypothesis when it is not true.

In this case study,

The null hypothesis is the standard deviation is less that or equal to 13min.

The alternative hypothesis would be that the standard deviation is greater than 13mins.

A type I error would occur when having done an experiment, the researcher rejects the null hypothesis when there is enough evidence that it is actually either less or equal to 13mins

A type II error would occur when the researcher fails to reject the null hypothesis when there is enough evidence that it is actually more than 13mins.

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89.10-[(1.20x31)+(4.90+7)]
lakkis [162]

Answer:

65.3

Step-by-step explanation:

89.10 - [(1.20 × 31)+ (4.90 + 7)]

89.10 - [37.2 + 11.9]

89.10 - 23.8

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Answer:

The hypotenuse is 7.62

Step-by-step explanation:

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