Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
Perpendicular
Step-by-step explanation:
Perpendicular lines meet at a 90 degree angle.
- 8 + 6 = - 2
Step-by-step explanation:
-2 = [-8] + 6
<u>-TheUnknownScientist</u>
Answer:
3
Step-by-step explanation:
Answer:
14:2 - 14 parts water and 2 parts salt
Step-by-step explanation:
The original ratio was 7:1. So, that means if you added another part to the salt it would make 2. That means that the 7 parts of water would become 14 parts. Since the ratio of the salt part was doubled from 1 to 2, you would have to do the same with the water ratio part. Hoped this helped!
