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Lyrx [107]
3 years ago
8

Henry buy a machine on January at a cost of 24,000 The machine is deprecated using the double declined method The

Mathematics
1 answer:
77julia77 [94]3 years ago
5 0

Answer:

12000

Step-by-step explanation:

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Please help ? i have no clue what i’m doing
Anit [1.1K]

Step-by-step explanation:

2( l + w ) = perimeter of triangle

P = 2( 10+8 )

p= 2(18)

p= 36cm

Circle = pie (r) + d. recall d = 2r

P= 3.142 (4) + 8

P= 20.57~

so therefore= , 36 + 2(20.57)= 77.14cm ~ to the nearest tenths

7 0
3 years ago
Write the equation of the line that passes through (2, 3) and is parallel to the line 12x – 5y = 2.
zheka24 [161]
The first thing I'd do is put this equation into standard slope - intercept form. 

12x - 5y = 2               Subtract 12x from each side
-5y = -12x + 2            Divide each side by -5 to isolate the <em>y 
</em><em />y = 12/5(x) - 2/5    
     
 The slope for this equation is 12/5, so we just take that and plug it into the slope - intercept equation with the given points (2, 3)

y = mx + b                    Fill in the variables
3 = 12/5(2) + b             Simplify
3 = 24/5 + b                 Subtract 24/5 (or 4 4/5) from each side
-9/5 = b

Now we just fill in the correct variables (m and b) in the equation to have our final answer. 

y = 12/5x - 9/5
4 0
2 years ago
Premium steak costs $18 per pound; how much steak cost per ounce ?
Angelina_Jolie [31]

Answer: $1.13 or $1.125

Step-by-step explanation:

divide 18 by 16

8 0
3 years ago
A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte
ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, q_1 = Q- r \times Q

q_1 = Q(1-r)\cdots(i)

The value of quantity after 2 months, q_2 = q_1- r \times q_1

q_2 = q_1(1-r)

From equation (i)

q_2=Q(1-r)(1-r)  \\\\q_2=Q(1-r)^2\cdots(ii)

The value of quantity after 3 months, q_3 = q_2- r \times q_2

q_3 = q_2(1-r)

From equation (ii)

q_3=Q(1-r)^2(1-r)

q_3=Q(1-r)^3

Similarly, the value of quantity after n months,

q_n= Q(1- r)^n

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

q_{48}=Q(1-r)^{48}

Putting Q=6200 and r=5.5%=0.055, we have

q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32

Hence, the value of quantity after 4 years is 410.32.

4 0
2 years ago
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A helicopter takes off from the ground 800 feet from the base of a building. It flies in a straight line directly to the top of
Sergio039 [100]
The angle from which helicopter take off approximately equals 11.30993247;
6 0
3 years ago
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