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strojnjashka [21]
4 years ago
12

What is the solution to this equation? 6x + 5 = 29

Mathematics
2 answers:
Finger [1]4 years ago
7 0
6x+5=29
29-5=24
6x=24
24/6=4
x=4

Maslowich4 years ago
4 0

Answer:

x=4

Step-by-step explanation:

6x+5=29

subtract 5 on both sides

6x=24

divide by 6 on both sides

x=4

hope this helps

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Adding 1/9 to both sides, we get 2/3+y=8/9. Next, 2/3 can be multiplied by 3/3 to get 6/9 due to that 3*3=9 and using the identity property. We then subtract 6/9 from both sides to get y=2/9
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Which could be the dimensions of a rectangular prism to service area is less than 160 ft.² check all that apply
raketka [301]

Area of rectangular prism is given by:

A=2(wl+hl+lw)

where w=width h=height, l=length

checking for given options

1. 8 ft, by 4ft by 3ft

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5. 3 feet by 5 feet by 7 feet

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4 years ago
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An artist used silver wire to make a square that has a perimeter of 40 inches. She then used copper wire to make the largest cir
finlep [7]

Answer:

The area of the copper circle is <u>31.4 inches</u>.

Step-by-step explanation:

Given:

An artist used silver wire to make a square that has a perimeter of 40 inches.

She then used copper wire to make the largest circle that could fit in the square, with perimeter of 40 inches.

Use 3.14 to represent π.

Now, to find the area of the copper circle.

Perimeter of square = 40 inches.

So, we get the side of square by putting formula:

Perimeter=4\times side

40=4\times side

Dividing both sides by 4 we get:

10=side.

Side=10\ inches.

Now, as the side of square is 10 inches it is the diameter of the circle as the square is fit inside the circle:

For getting the area of circle we find the radius:

Radius (r) = \frac{Diameter}{2} \\=\frac{10}{2}= 5\ inches.

Now, putting the formula to get the area of the circle:

Area=2\times \pi \times r

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6 0
3 years ago
Simplify the rational expression.  State any restrictions on the variable.
AveGali [126]

Answer:

The last choice.

Step-by-step explanation:

\dfrac{k^2-k-2}{k^2-4k-5}=\dfrac{(k+1)(k-2)}{(k+1)(k-5)}=\dfrac{k-2}{k-5}

The value of k must be restricted from being one that makes the original denominator zero. Hence k ≠ -1 or 5.

7 0
3 years ago
The function ƒ(x) = (x − 1)^2 + 5 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an i
melisa1 [442]

Answer:

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Step-by-step explanation:

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Sqrt(y-5)=x-1

Add 1 on both sides:

Sqrt(y-5)+1=x

Swap x and y:

Sqrt(x-5)+1=y

x>5

y>1

3 0
3 years ago
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