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Arturiano [62]
3 years ago
9

The ratio of the ages (in years) of three children is 2:4:5. The sum of their ages is 33. What is the age of each child?

Mathematics
1 answer:
pickupchik [31]3 years ago
5 0
We have 2x + 4x + 5x = 33 so 11x = 33 and x 3.

The children are 6, 12 and 15
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F(x)=4/x<br> g(x)=4/x <br><br> Find f(g(x))
qaws [65]
The answer of the question is x.
4 0
3 years ago
Conti. 7-10 thanks a lot! <br><br>unhelpful answers will be deleted.​
Marysya12 [62]

Answers:

10. b. \displaystyle 13

9. b. \displaystyle 20

8. a. \displaystyle 33

7. a. \displaystyle 25°

Step-by-step explanations:

10. Both segments are considered congruent, so turn both expressions into an equation:

\displaystyle 3x - 5 = x + 7 \hookrightarrow \frac{-12}{-2} = \frac{-2x}{-2} \\ \\ 6 = x

Plug this back into the equation to get \displaystyle 13on both sides.

9. All edges in a square obtain congruent right angles and edges, so set \displaystyle 45equivalent to the given expression:

\displaystyle 45 = 2x + 5 \hookrightarrow \frac{40}{2} = \frac{2x}{2} \\ \\ \boxed{20 = x}

8. Both angles are considered supplementary, so turn both expressions into an equation and set it to one hundred eighty degrees:

\displaystyle 180 = (4x - 15)° + (x + 30)° \hookrightarrow 180° = (15 + 5x)° \hookrightarrow \frac{165}{5} = \frac{5x}{5} \\ \\ \boxed{33 = x}

7. In this rectangle, segment <em>EO</em><em> </em>is a segment bisectour, making these angles <em>Complementary</em><em> </em><em>Angles</em><em>.</em><em> </em>Therefore, set an equation up to find its complement:

\displaystyle 90° = 65° + m\angle{VOE} \\ \\ \boxed{25° = m\angle{VOE}}

I am joyous to assist you at any time.

3 0
2 years ago
If an event has a 55% chance of happening in one trial, how do I determine the chances of it happening more than once in 4 trial
aev [14]

The chances of it happening more than once in 4 trials is 13%

<h3>How to determine the number</h3>

From the information given, we have can deduce that;

Probability of 1 trial = 55%

= 55/ 100

Find the ratio

= 0. 55

We are to find the probability of it happening more than once in 4 different trials

If the probability of it happening in one trial is 555 which equals 0. 55

Then the probability of it happening in 1 in 4 trials is given as;

P(1/4 trials) = 1/ 4 × 55%

P(1/4 trials) = 1/ 4 × 0. 55

Put in decimal form

P(1/4 trials) = 0. 25 × 0. 55

P(1/4 trials) = 0. 138

But we have to know the percentage

= 0. 138 × 100

Multiply the values, we have

= 13. 8 %

Thus, the chances of it happening more than once in 4 trials is 13%

Learn more about probability here:

brainly.com/question/24756209

#SPJ1

6 0
2 years ago
James age is 3 years less than twice Tori's age the sum of their ages is 30 find their ages
blagie [28]
Error// Error// Error// Error// Error// Error//
7 0
3 years ago
A marble is selected at random from a jar containing 3 red​ marbles, 4 yellow​ marbles, and 6 green marbles. What is the probabi
alexgriva [62]

Answer:  a) \dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}

Step-by-step explanation:

Since we have given that

Number of red marbles = 3

Number of yellow marbles = 4

Number of green marbles = 6

Total number of marbles = 3 +4 +6 = 13

​a) the marble is​ red? ​

Probability of getting a red marble = \dfrac{3}{13}

b) the marble is not​ yellow?

Probability of not getting yellow = \dfrac{3+6}{13}=\dfrac{9}{13}

​c) the marble is either red or ​green?

Probability of getting either red or green = P(red) + P(green) =\dfrac{3}{13}+\dfrac{6}{13}=\dfrac{9}{13}

d) the marble is neither red nor ​green?

Probability of getting neither red nor green = P(getting yellow) = \dfrac{4}{13}

Hence, a) \dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}

5 0
3 years ago
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