Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
Answer: 
Step-by-step explanation:
Group like terms:
Simplify the arithmetic:
Add 7 to both sides:
Simplify the arithmetic:
Simplify the arithmetic:
Divide both sides by 3:
Simplify the fraction:
Find the greatest common factor of the numerator and denominator:
Factor out and cancel the greatest common factor and the answer will be:
Answer
Step-by-step explanation:
i need the form of opperations what are you doing? standard form algerbraic roots with mixed fractions?
Answer:
567
Step-by-step explanation:
It will become:
y = 7(3)^4
y = 7 * 81
y = 576
Answer:
y = (2/5)x + 3
Step-by-step explanation:
Note that the y-intercept is (0, 3) and that the line passes right through the point (5, 5). First we find the slope of this line: m = rise/run.
As we move from (0, 3) to (5, 5), we see that x increases by 5 (the run) and y increases by 2 (the rise). Thus, the slope of this line is m = 2/5.
Now we know that m = 2/5, x = 5, y = 5 and b (the y-intercept) is 3. Then our equation is y = mx + b, or y = (2/5)x + 3
