y = x + 4/x
replace x with -x. Do you get back the original equation after simplifying. if you do, the function is even.
replace y with -y AND x with -x. Do you get back the original equation after simplifying. If you do, the function is odd.
A function can be either even or odd but not both. Or it can be neither one.
Let's first replace x with -x
y = -x + 4/-x = -x - 4/x = -(x + 4/x)
we see that this function is not the same because the original function has been multiplied by -1
. Let's replace y with -y and x with -x
-y = -x + 4/-x
-y = -x - 4/x
-y = -(x + 4/x)
y = x + 4/x
This is the original equation so the function is odd.
9514 1404 393
Answer:
obtuse
Step-by-step explanation:
The law of cosines tells you ...
b² = a² +c² -2ac·cos(B)
Substituting for a²+c² using the given equation, we have ...
b² = b²·cos(B)² -2ac·cos(B)
We can subtract b² to get a quadratic in standard form for cos(B).
b²·cos(B)² -2ac·cos(B) -b² = 0
Solving this using the quadratic formula gives ...

The fraction ac/b² is always positive, so the term on the right (the square root) is always greater than 1. The value of cos(B) cannot be greater than 1, so the only viable value for cos(B) is ...

The value of the radical is necessarily greater than ac/b², so cos(B) is necessarily negative. When cos(B) < 0, B > 90°. The triangle is obtuse.
In order to answer that question, we need to know the scale of the map.
Without that information, no answer is possible.
I think you have it in the first part of the question ... the part you decided
not to post.
_________________________
OK. Now that you've provided the scale of the map,
answering the question is a piece-o-cake.
Use a proportion:
(1 inch on the map) / (4 miles on the ground) = ('x' on the map) / (17 miles on the ground)
we know that
The least
common multiple (LCM) of two or more numbers is the least
number, other than zero, that is a multiple of all the numbers.
In this problem, we are looking for the least common multiple of
and
So
Multiply
by 

therefore
On the
day after today, she will do both on the same day
the answer is
