The slope is 3.5, also known as 3 1/2.
Answer:
It should be linear if you let the variable t represent the time tutoring for ONE student, so y = 40*t where t = number of hours for ONE student
so if the tutor taught 2 students for 2 hours together, then t = 2*2 = 4 hours
Step-by-step explanation:
y = 40t
t = tutoring hours for ONE unique student...
Answer:
Step-by-step explanation:
When Riko left his house, Yuto was 5.25 miles along the path.
Average speed of Riko = 0.35 miles per minute
Average speed of Yuto = 0.25 miles per minute
First we will calculate the time in which Riko will catch Yuto on the track.
Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto
= 0.35 - 0.25
= 0.10 miles per minute
Now we this relative velocity tells that Riko is moving and Yuto is in static position.
By the formula,
Average speed = 
0.10 = 
t = 
t = 52.5 minutes
Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.
So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5
Here time can not be less than zero because time can not be with negative notation. It will always start from 0.
Answer:
c. x=50; m< LOK = 114
Step-by-step explanation:
(x+64) + 66 = 180
x + 130 = 180
x = 50
I would have to say -7(1/8)x-4/3=20.
The first and the second one both result in
-23 5/7
The last one results in -24 8/21
but the third one is -22 3/8.
So your answer is either the third of the last one. I assumed the third because, it is lower than all others and the first two are closer to 24 than they are to 22. It’s your choice on how to judge it.