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Aleonysh [2.5K]
3 years ago
15

Find the sum for the polynomials

Mathematics
1 answer:
Nana76 [90]3 years ago
4 0
I don’t think you can get a hold of me and
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1) Expand and simplify the following:<br>a)3(x squared plus 3x cubed - 2)​
Musya8 [376]

Answer:

3x³ + x² - 2

Step-by-step explanation:

a) 3(x squared plus 3x cubed - 2)​

x squared = x²

3x cubed = 3x³

3(x squared plus 3x cubed - 2)​

= 3(x² + 3x³ - 2)

= 3x² + 9x³ - 6

Rearrange according to power

= 9x³ + 3x² - 6

When the expression is divided by 3, it is equivalent to

3x³ + x² - 2

5 0
3 years ago
1 quart is equal to 4 cups given this fact what is 8 quarts equivalent to in cups
SVETLANKA909090 [29]
8 quarts is equal to 32 cups :)
5 0
3 years ago
Hudson runs 4 miles per day. What is the relationship between the number of days and how many miles he has run
Citrus2011 [14]

Answer:

Running 3 miles a day, paired with a healthy diet and lifestyle habits, can help you burn excess body fat. ... The key to losing weight is establishing a caloric deficit, or burning more calories than you take in, and running is great for burning calories.May 28, 2019

Step-by-step explanation:

6 0
3 years ago
A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit
Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = -  (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] =  20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0
3 years ago
Kevin is 3 times as old as Daniel. 4 years ago, Kevin was 5 times as old as Daniel.
rusak2 [61]

Answer:

24

Step-by-step explanation:

4 years ago, Daniel would've been 4 and Kevin would be 20, so Kevin would've been 5 times as old as Daniel. And 8 x 3 = 24. So, Kevin is 24.

4 0
3 years ago
Read 2 more answers
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