To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
A=p(1+i/m)^mn
A=3,500×(1+0.0229÷12)^(12×6)
A=4,014.98
Answer:
6y^3x^3-y^2x^3
Step-by-step explanation:
Answer:
0.16666
Step-by-step explanation:
100/60
Answer:
400
Step-by-step explanation:
