2 years ago

Kevin has a deck of cards. There are 10diamonds, 5 spades, 12 clubs and 3 hearts.A card was chosen at random. What is the

1 answer:

ivann1987 [24]2 years ago

5 0

Answer: 2/3.

Step-by-step explanation: When you add all the spades, hearts, clubs, and diamonds cards together, you get 30 in total. 1/3 of the 30 cards in total are diamonds, so the other 2/3 can be drawn as well. The probability of not choosing a diamond card is 2/3, since the remaining 1/3 is all diamonds.

Have a great day! :)

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Write an expression for the verbal phrase: The difference between x and half of y.

zmey [24]

Answer:

Step-by-step explanation:

half of y = 1/2 *y

Difference between x and half of y

= x - 1/2 y

4 0

3 years ago

Which of the following is correctly written in Standard Form? −3x + 7y = 12, y = 3/7x + 6 ,5x − 4y = 9 ,3/7x + 2y =9

melisa1 [442]

2nd one - y = 3/7x + 6 , hope this helps:)

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3 years ago

Write 3x 3x 3x 3 x 3 using exponents

Ahat [919]

$3\cdot3\cdot3\cdot3\cdot3=3^5$

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3 years ago

How does the product of 2 × 6 compare to the product of 10 × 6?

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D should be it cause it

6 0

3 years ago

Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
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$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$

4 0

3 years ago