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Tcecarenko [31]

3 years ago

6

Renee is wanting to join a gym.

1 answer:

WINSTONCH [101]3 years ago

7 0

Pumping iron: 10x+90=0
Fit for life: 15x+50=0

Set them equal to each other. 10x+90=15x+50. Solve for x. Subtract 50 from both sides, get 10x+40=15x, then subtract 10x from both sides, getting 40=5x. Divide 5 from both sides to isolate x, x=8. After 8 months the two gyms will cost the same.

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Jon goes to a flea market and sells comic books for 3 dollars each. He starts the night with 20 dollars in

Rudiy27

So what you have to do to figure this out is 47-20 to get 27, then take 27 and divide it by 3 to get the answer of 9 comic books were sold by John.

5 0

2 years ago

(4x2 - 6x + 1) divided by (x-2)

Dennis_Churaev [7]

Answer:

x-2

Step-by-step explanation:

3 0

3 years ago

A 45-pound bag of rice is going to be split between 5 families. How much rice will each family receive?

Artemon [7]

Answer:

9 pounds per family

Step-by-step explanation:

45/5=9

hope this helps

can i plz get brainliest?

6 0

3 years ago

Read 2 more answers

Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

kvv77 [185]

The question is an illustration of composite functions.

Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

$5000 in fixed costs plus an additional $250
5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

<u>(b) Function c(n(h))</u>

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

<u>(d) Interpret (c)</u>

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0

3 years ago

Write the following number as ratios of integers

Grace [21]

We're going to "cut" the repeating part here in a few steps. First, we're going to put the number in a variable:

$x=-2.0\overline{42}$

Next, to get rid of the negative, we can multiply either side by -1 to get

$-x=2.0\overline{42}$

Now, we won't actually use this -x directly; instead, we want to create two new values, one by multiplying either side by 10:

$-10x=20.\overline{42}$

and the other by multiplying either side by 1000:

$-1000x=2042.\overline{42}$

Next, we can get rid of the repeated part of the number by subtracting -10x from -1000x:

$-1000x-(-10x)=2042.\overline{42}-20.\overline{42}\\ -1000x+10x=2022\\ -990x=2022$

And finally, we can divide either side of the equation by -990 to find that

$x= \frac{2022}{-990}=-\frac{2022}{990}\div \frac{6}{6}=-\frac{337}{165}$

5 0

3 years ago